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DiKsa [7]
3 years ago
7

I’ll give the Brainliest to who answers this question with a reasonable explanation.

Mathematics
1 answer:
Lyrx [107]3 years ago
5 0
$40/12 = unit rate simplify = 10/3
$10/3 per book
18 * 10/3 = $60 for 18 copies
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Tell which value of the variable, if any, is a solution to the equation.
kvasek [131]

Answer:

14

Step-by-step explanation:

14+9=25

4 0
3 years ago
For the point P(17.-9) and Q(24. - 4), find the distance d{P.Q) and the coordinates of the midpoint M of the
Elza [17]

Answer:

im pretty sure this is the answer :) ym = (y1 + y2)/2

Step-by-step explanation:

7 0
3 years ago
TRUE OR FALSE: FOR ANY FUNCTION, X=F^-1(Y), THEN Y=F(X). PLEASE EXPLAIN
Vesnalui [34]

Answer:

True.

Step-by-step explanation:

For example let f(x) = 3x + 1  then f-1(x)  is found as follows

Let f(x) = y = 3x + 1 then

3x = y - 1

x = (y-1) / 3

x = f-1(x) = (x - 1)/3.

So:

Replacing the x  in y by (x - 1)/3 :-

x = f(-1)(y) = ( (3x + 1) - 1) / 3

= 3x / 3

= x.

So y = f(x).

7 0
3 years ago
It takes 1 1/3 hours to set up 1/3 of an hour to run and 2/3 of an hour to verify the results. How many hours will it take to co
liraira [26]

Answer: It will take \frac{7}{3} of an hour to complete the test.

Step-by-step explanation:

We need to convert the mixed number 1\ \frac{1}{3} to an improper fraction:

1\ \frac{1}{3}=\frac{(1*3)+1}{3}= \frac{4}{3}

Now, we need to make the following add the fractions in order to calculate how many hours will it take to complete the test. Then, we get:

\frac{4}{3}+\frac{1}{3}+\frac{2}{3}=\frac{4+1+2}{3}=\frac{7}{3}

Therefore, it will take \frac{7}{3} of an hour to complete the test.

5 0
4 years ago
Evaluate the expression x - 7. If x= 12.<br> 19<br> 6<br> 17<br> 5
ratelena [41]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{5}}}}}

Step-by-step explanation:

Given , value of x = 12

To find : Value of the given expression

Given expression = \sf{x - 7 }

plug the value of x

\dashrightarrow{ \sf{ 12 - 7}}

Subtract 7 from 12

\dashrightarrow{ \sf{5}}

Hope I helped!

Best regards! :D

8 0
4 years ago
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