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Bingel [31]
3 years ago
13

Solve the system of equations.

Mathematics
1 answer:
morpeh [17]3 years ago
3 0

Answer:

y=3,x=1.3,z=6.2 :)

Step-by-step explanation:

y=3,x=1.3,z=6.2 :)

So, we have:

   : x+y+z=10 [equation 1]

   : 5x+3y=14  [equation 2]

   : x−2y+z=2.5 [equation3]

(I'm going to assume that you know how to solve equations with 2 variables)

1. eliminate a variable to get 2 variables

Let's reverse equation 2:

-x+2y-z= -2.5

and take equation 1, to try to eliminate "z"

x+y+z=10

add up the 2 equations to get:

3y=7.5

and solve to get

y=2.5

2. substitute what we already solved into another equation

Luckily, equation 2 only has 2 variables, and one is y, so we can sub it in.

5x+3y=14 --> 3x+3(7.5)=14

solve to get

x=1.3

3. Substitute both of our variables in to get the final variable: z

Let's take the first equation.

x+y+z=10 --> 1.3+2.5+z=10

solve to get

z=6.2

I hope this helps you!

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Exclude leap years from the following calculations. ​(a) Compute the probability that a randomly selected person does not have a
Scrat [10]

Answer:

a) 99.73% probability that a randomly selected person does not have a birthday on March 14.

b) 96.71% probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

c) 98.08% probability that a randomly selected person does not have a birthday on the 31 st day of a month.

d) 92.33% probability that a randomly selected person was not born in February.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

A non-leap year has 365 days.

​(a) Compute the probability that a randomly selected person does not have a birthday on March 14.

There are 365-1 = 364 days that are not March 14. So

364/365 = 0.9973

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​(b) Compute the probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

There are 12 months, so there are 12 2nds of a month.

So

(365-12)/365 = 0.9671

96.71% probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

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The following months have 31 days: January, March, May, July, August, October, December.

So there are 7 31st days of a month during a year.

Then

(365-7)/365 = 0.9808

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(d) Compute the probability that a randomly selected person was not born in February.

During a non-leap year, February has 28 days. So

(365-28)/365 = 0.9233

92.33% probability that a randomly selected person was not born in February.

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bonufazy [111]
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So tan(52) = 1.28 ish. So we know that x/18 = 1.28.
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x / 18 * 18 = 1.28 * 18

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3 years ago
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