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Bingel [31]
3 years ago
13

Solve the system of equations.

Mathematics
1 answer:
morpeh [17]3 years ago
3 0

Answer:

y=3,x=1.3,z=6.2 :)

Step-by-step explanation:

y=3,x=1.3,z=6.2 :)

So, we have:

   : x+y+z=10 [equation 1]

   : 5x+3y=14  [equation 2]

   : x−2y+z=2.5 [equation3]

(I'm going to assume that you know how to solve equations with 2 variables)

1. eliminate a variable to get 2 variables

Let's reverse equation 2:

-x+2y-z= -2.5

and take equation 1, to try to eliminate "z"

x+y+z=10

add up the 2 equations to get:

3y=7.5

and solve to get

y=2.5

2. substitute what we already solved into another equation

Luckily, equation 2 only has 2 variables, and one is y, so we can sub it in.

5x+3y=14 --> 3x+3(7.5)=14

solve to get

x=1.3

3. Substitute both of our variables in to get the final variable: z

Let's take the first equation.

x+y+z=10 --> 1.3+2.5+z=10

solve to get

z=6.2

I hope this helps you!

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The diameter of 0 gauge copper wire is 8.252 mm. Find the resistance (in ω) of a 2.40 km length of such wire used for power tran
VashaNatasha [74]

d = diameter of the copper wire = 8.252 mm

r = radius of the copper wire = d/2 = 8.252 mm /2 = 4.126 mm = 0.004126 m

A = area of cross-section of the copper wire = πr² = (3.14) (0.004126)² = 53.5 x 10⁻⁶

L = length of the copper wire = 2.40 km = 2400 m

ρ = resistivity of copper wire = 1.68 x 10⁻⁸

resistance of copper wire is given as

R = ρL/A

inserting the above values in the formula

R = ( 1.68 x 10⁻⁸)(2400)/(53.5 x 10⁻⁶)

R = 0.753 ohm

8 0
4 years ago
A car drives at an average speed of 54km/h for 1 hour and 20 minutes. What was the distance covered by the car in km?​
VLD [36.1K]

Answer:

\huge\boxed{\sf S = 71.82\ km}

Step-by-step explanation:

<u>Given:</u>

Speed = v = 54 km/h

Time = 1 hour 20 min = 1 hour (20/60) hour = 1.33 hrs

<u>Required:</u>

Distance = S = ?

<u>Formula:</u>

S = vt

<u>Solution:</u>

S = (54)(1.33)

S = 71.82 km

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
8 0
3 years ago
Read 2 more answers
What is the answer to 8.5+4(1-2.5k)=-24.5
CaHeK987 [17]
8.5+(4×1)+(4×-2.5k)=-24.5
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(8.5+4)+(-10k)=-24.5
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4 0
4 years ago
What is 6 squared divided by 2(3) + 4?
prohojiy [21]
6^2/2(3)+4=36/2(3)+4=18(3)+4=54+4=58 \\ \\ or \\ \\ \frac{6^2}{2(3)+4} = \frac{36}{6+4}= \frac{36}{10} =3.6 \\  \\ or \\  \\  \frac{6^2}{2(3)}+4 = \frac{36}{6}+4=6+4=10

It all depends on how the equation is written.
4 0
3 years ago
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harina [27]

Answer: To find the excluded value in the domain of the function, equate the denominator to zero and solve for x .

Step-by-step explanation:

For example, in the problem below The domain of the function is set of real numbers except −3 . The range of the function is same as the domain of the inverse function. So, to find the range define the inverse of the function.

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