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ki77a [65]
3 years ago
5

A plumber had two pipes. The ratio of the length of the longer pipe to the shorter pipe was 9:2. When he cut 1.65m from the long

er pipe, the remaining length was 3 times that of the shorter pipe. Find the length of the shorter pipe in metres.
Mathematics
1 answer:
Natasha2012 [34]3 years ago
6 0

Answer:

1.1m

Step-by-step explanation:

Let L denote longer pipe and S denote shorter part

given:

L:S = 9:2

or L/S = 9/2

2L = 9S

S = (2/9)L-----(eq 1)

Also given:

L - 1.65 = 3S

L - 3S = 1.65 ----- (eq 2)

By substitution, sub eq 1 into eq 2

L - 3(2/9)L = 1.65

L - (2/3)L = 1.65

L [ 1 - (2/3) ] = 1.65

L/3 = 1.65

L = 1.65 (3) = 4.95  (substitute into equation 1)

S = (2/9)(4.95) = 1.1m

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We can change the mixed number to a decimal for comparing.

1\frac{1}{4} m = \frac{5}{4} m = 1.25 m

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Darren   >     Luke

Darren's jump was higher by (1.4-1.25) 0.15 m

Or another way change the decimal to a fraction and the mixed to an improper fraction too.

1\frac{1}{4} = \frac{5}{4} (Luke)
1.4 = \frac{7}{5}                               (Darren)
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\frac{5*5}{4*5}       (Luke)
\frac{7*4}{5*4}       (Darren)
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\frac{28}{20}  >   \frac{25}{20}
        Darren           >            Luke
  
By:
\frac{28}{20} - \frac{25}{20} = \frac{3}{20}
Which is also by 0.15 m
Darren jumps higher and by 0.15 m
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