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sveticcg [70]
3 years ago
12

Two composite numbers with one factor tree

Mathematics
2 answers:
katen-ka-za [31]3 years ago
8 0
By definition, a prime number is only evenly divisible by itself, or the number 1, and it is greater than 1. If a number is composite, you can divide it evenly by numbers other than 1. For example, if you divide 7 by any integer other than 1, you end up with a fraction or decimal; therefore, 7 is prime. However, 8 is divisible by 2 and 4 (8/2 = 4, 8/4 = 2). Breaking down a number into its prime and composite factors is helpful for a number of mathematical processes.
<span>Hope that works out! :D</span>

Nonamiya [84]3 years ago
6 0
I can't make a tree very easily but I will still answer you question

a composite number, if you did not already know, is a number that can be divided by a diffarent whole number and still get a whole number (exg. 4/2=2=composite  5/2=a decimal=prime)

so one composit number is 16
the factored out tree is 2*8
                                     2*4
                                       2*2

another is 24
 the factor tree is 2*12
                              2*6
                                   2*3
hope you can see the tree as I typed it out
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Part 3 - Discussion/Explanation Question
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Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

\frac{1}{x - 5}

Set the expression in the denominator equal to 0, because you can't divide by 0.

x - 5 = 0

x = 5

So the vertical asymptote is x=5.

Disclaimer if you see something like this

\frac{(x - 5)(x + 3)}{(x - 5)}

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

\frac{1}{x}

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

a \times  {x}^{0}

For example,

1 = 1 \times  {x}^{0}

2 =  2 \times {x}^{0}

And so on,

and

x =  {x}^{1}

So our equation is basically

\frac{1 \times  {x}^{0} }{ {x}^{1} }

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

\frac{3 {x}^{2} }{ {x}^{2}  + 1}

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

x =  \frac{3}{1}

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

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Answer:

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Answer:

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