Question

Can somebody please help me

Answer 1

Here is your answer

B. (12,30)

REASON:

Given,

$y= 2x+6$ .......(i)

$3x-y= 6$ .......(ii)

Putting the value of y from eq.i in eq.ii we get

$3x-(2x+6)=6$

$3x-2x-6=6$

$=6+6$

$x=12$

Putting x=12 in eq.i we get

$y= 2x+6$

$y= 2×12+6$

$y= 24+6$

$y= 30$

So,

$\bold{x=12 and y= 30}$

Hence answer is (12,30) in which x=12 and y=30

HOPE IT IS USEFUL