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jasenka [17]
3 years ago
10

What are the solutions to the equationx^2+14x=-130please do a step by step

Mathematics
1 answer:
Serjik [45]3 years ago
5 0

Answer:

The answer to your question is:  x1 = - 7 + 9i      x2 = -7 - 9i

Step-by-step explanation:

                                             x² + 14x = - 130

                                            x² + 14x + (7)² = -130 + (7)²

                                           (x + 7)² = -81

                                            x + 7 = ± √-81

         i² = -1,  then                x + 7 = ±√ 81i²

                                            x + 7 = ± 9i

                          x1 = -7 + 9i                         x2 = -7 - 9i

                                             

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Talja [164]

Answer:

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Step-by-step explanation:

We are given the following expression in the question:

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One of the zeroes of the above polynomial is 2i, that is :

f(x) = x^3 - 4x^2+ 4x - 16\\f(2i) = (2i)^3 - 4(2i)^2+ 4(2i) - 16\\= -8i+ 16+8i-16 = 0

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Now, we check if -2i is a root of the given polynomial:

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(x-2i)(x+2i)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16\\(x^2 + 4)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16

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BlackZzzverrR [31]
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printed paper)
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Hope that helps! Have a good day :)
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