D because the rest can be divided into cubes or rectangles.
Answer:
The chance that there will be exactly 2 heads among the first five tosses and exactly 4 heads among the last 5 tosses is P=0.0488.
Step-by-step explanation:
To solve this problem we divide the tossing in two: the first 5 tosses and the last 5 tosses.
Both heads and tails have an individual probability p=0.5.
Then, both group of five tosses have the same binomial distribution: n=5, p=0.5.
The probability that k heads are in the sample is:
Then, the probability that exactly 2 heads are among the first five tosses can be calculated as:
For the last five tosses, the probability that are exactly 4 heads is:
Then, the probability that there will be exactly 2 heads among the first five tosses and exactly 4 heads among the last 5 tosses can be calculated multypling the probabilities of these two independent events:
Answer:
R = 23.9
Step-by-step explanation:
formula for circles circumfrence is, C = 2*3.14*R
in this one we have to work backwards so we plug wut we have.
150 = 2* 3.14*R
we divide 150 by 2 so it will be
75 = 3.14R
now we divide 75 by pi so wwe get
23.8732414638 = R
Now we round it to nearest tenth
R = 23.9
Jane times everything by 100
karen timed 1.25 by 100
scott added x and 1.25x together
Answer:
105.3
Step-by-step explanation:
cos(70)= 36/x
x=36/cos(70)
x=105.256958406
x~105.3