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7nadin3 [17]
3 years ago
8

Q2

Mathematics
1 answer:
MariettaO [177]3 years ago
7 0

Answer:

20cm^3

Step-by-step explanation:

V = w x h

w = width

h = height

5x4 = 20

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I need help this is algebra one and it is due tomorrow need help on this question.number 15
Mademuasel [1]
(p>64) divided by 4 is less than or equal to w
5 0
3 years ago
Gisselle has 1/2 of a candy bar. She role off 1/2 of what she had. She then took the piece she broke off and split it into three
saul85 [17]

Answer:

\frac{1}{12}

Step-by-step explanation:

Given:

Gisselle has 1/2 of a candy bar.

She role off 1/2 of what she had and split it into three equal pieces.

Question asked:

What fraction of a candy bar was each piece?

Solution:

Gisselle has = \frac{1}{2} \ of \ a \ candy \ bar

She role off = \frac{1}{2} \ of \ what\ she \ had

                     =\frac{1}{2}  \ of\  \frac{1}{2}\\=\frac{1}{2} \times \frac{1}{2}\\\\=\frac{1}{4}

As she split it into three equal pieces, we will divided it by 3, we get,

\frac{1}{4} \div3\\\frac{1}{4}\times\frac{1}{3}

\frac{1}{12}

Therefore, fraction of a candy bar of each piece is \frac{1}{12}

4 0
2 years ago
X = b - cd, solve for c
Sliva [168]
C=b/d-x/d,Recomend you watch https://www.youtube.com/watch?v=QQoPAU5L52s
8 0
3 years ago
A skyscraper casts a shadow 200 feet long. If the angle of elevation of the sun is 49 , then the height of the skyscraper is ___
Nookie1986 [14]
Based on the information, you could find it using this formula :

Assuming the height of the skyscraper is coded as 'y'

Tan 49 = y/200

1.1504 = y/200

y = 230.8 Feet

hope this helps
7 0
3 years ago
Read 2 more answers
Let $r$ and $s$ be the roots of $3x^2 + 4x - 12 = 0.$ Find $r^2 + s^2.$
Paul [167]

We can factorize the quadratic as

3x^2 + 4x - 12 = 3 (x - r) (x - s)

and expand the right side to get

3x^2 + 4x - 12 = 3x^2 - 3(r + s) x + 3rs

\implies r + s = -\dfrac43 \text{ and } rs = -4

Then we find

(r + s)^2 = r^2 + 2rs + s^2 \implies r^2 + s^2 = \left(-\dfrac43\right)^2 - 2(-4) = \boxed{\dfrac{88}9}

8 0
2 years ago
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