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Volgvan
3 years ago
6

I NEED HELP

Mathematics
2 answers:
noname [10]3 years ago
6 0

Answer:

You can use a number line to subtract -6 from -7. The difference is -1.

blsea [12.9K]3 years ago
6 0

Answer:

Rules for Subtracting Integers

Date: 10/31/2001 at 10:41:08

From: Julie

Subject: Rules for subtracting integers

For my assignment I need to write rules for subtrating integers. I

don`t know where to get this information.

Date: 10/31/2001 at 16:58:52

From: Doctor Peterson

Subject: Re: Rules for subtracting integers

Hi, Julie.

I don't tend to use "rules"; it works better to base what I do on an

understanding of how things work. Let's look at how things work, and

then you can see if you can express that in a simple set of rules.

If we put two numbers on the number line, then when we subtract A

from B, we get the "directed distance" from A to B:

                        B-A

                +----------------->

   <------------o-----------------o------------------------->

                A                 B

That is, B-A is the number you have to add to A in order to get B:

   A + (B-A) = B

If B > (is greater than) A, as shown, then B-A is a positive number

(the arrow goes to the right). But if B < (is less than) A, then the

difference will be negative:

                        B-A

                <-----------------+

   <------------o-----------------o------------------------->

                B                 A

In fact, B-A is exactly the opposite of A-B:

   B-A = -(A-B)

So you can subtract a larger number from a smaller one by subtracting

the other way around and sticking a negative sign on the answer.

That's a rule you can use.

Another fact you may want to use is that if you have a number in

between, the difference is the sum of the two intermediate

differences:

                        B-A           C-B

                +----------------->--------->

   <------------o-----------------o---------o--------------->

                A                 B         C

                +--------------------------->

                             C-A

   C-A = (B-A) + (C-B)

Notice that I deliberately didn't indicate on the number line whether

A and B are positive or negative; I didn't show where zero is. That's

because this definition of subtraction doesn't care about that. But

when you actually try to subtract two numbers, it will matter. And 0

may play the role of A, B, or C in this picture. For example, if B is

zero, since 0-A is -A, and C-0 is just C, this says that

   C-A = -A + C

Since A is a negative number, -A is positive, and this gives a way to

subtract a negative number from a positive by just adding two positive

numbers, something you already know how to do.

There are three places where I could have put the zero, and each

corresponds to a different case you may want to consider when you

write your rules. Try writing a rule to find B-A in each of these

cases:

1. A and B are both positive:

                         A            B-A

                +----------------->--------->

   <------------o-----------------o---------o--------------->

                0                 A         B

                +--------------------------->

                              B

2. A is negative and B is positive:

                         -A            C

                +----------------->--------->

   <------------o-----------------o---------o--------------->

                A                 0         B

                +--------------------------->

                             B-A

3. A and B are both negative:

                        B-A           -B

                +----------------->--------->

   <------------o-----------------o---------o--------------->

                A                 B         0

                +--------------------------->

                             -A

In each case, you will want to consider which number is larger (and in

case 2, that means which of the two is positive); I've only shown B

larger. This will give you six cases; you may find a way to simplify

your rules by combining related cases. Have fun finding a way to say

all this neatly! Really, it can all be done with those two little

"rules" I gave above:

   B-A = -(A-B)

and

   B - A = B + -A

Just put these together a little differently in each case.

Step-by-step explanation:

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Plug in what we know.

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8 0
3 years ago
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8 0
3 years ago
in a city school of 1,200 students, 40% of the students are on the honor roll, 60% have a part-time job, and 22% are on the hono
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Let
A = event that the student is on the honor roll
B = event that the student has a part-time job
C = event that the student is on the honor roll and has a part-time job

We are given
P(A) = 0.40
P(B) = 0.60
P(C) = 0.22
note: P(C) = P(A and B)

We want to find out P(A|B) which is "the probability of getting event A given that we know event B is true". This is a conditional probability

P(A|B) = [P(A and B)]/P(B)
P(A|B) = P(C)/P(B)
P(A|B) = 0.22/0.6
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Convert this to a percentage to get roughly 36.67% and this rounds to 37%

Final Answer: 37%

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3 years ago
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