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Sloan [31]
4 years ago
10

Margo practices her flute 1/4 hour each day. Write and solve an equation to find how many hours Margo practices her flute in 1 w

eek. Write and solve an equation to find how may minutes Margo practices her flute in 1 day. Then
use that to find the number of minutes she practices in 1 week.
Mathematics
2 answers:
Nadya [2.5K]4 years ago
8 0

Answer:

<u>Part A:</u> Write and solve an equation to find how many hours Margo practices her flute in 1 week.

Let the number of days = x

Margo practices her flute 1/4 hour each day.

Total number of hours = \frac{1}{4}x

Week = 7 days

So, the number of hours Margo practices her flute in 1 week = \frac{1}{4}*7=\frac{7}{4}=\frac{4+3}{4}=1\frac{3}{4}   \ hours

<u>Part B:</u> Write and solve an equation to find how may minutes Margo practices her flute in 1 day.

Let the number of minutes = y

Total number of minutes = \frac{1}{4} y

Hour = 60 minutes

Substitute with y = 60

So, the number of minutes Margo practices her flute in 1 day =

\frac{1}{4}*60=15 minutes

The number of minutes she practices in 1 week = 15 * 7 = 105 minutes.

4vir4ik [10]4 years ago
3 0

Answer:

Margo practices her flute 42 hours a week. She practices 360 minutes per day. 2520 minutes per week

Step-by-step explanation:

24 hours a day divided by 4 =6 6 x 7 days per week=42 hours. 6 hours x 60 minutes= 320 minutes. 320 minutes per day x 7 days =2520 minutes per week

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Select the point that is a solution to the system of inequalities
Zarrin [17]
<h2>Hello!</h2>

The answer is:

The point that is a solution to the system of inequalities is C(4,2).

<h2>Why?</h2>

To find the point that is a solution to the system of inequalities, we need to evaluate it into the given inequalities. If the point is a solution to the system of inequalities, both inequalities will be satisfied.

We are given the inequalities:

y\leq 2x-2

y\leq x^{2} -3x

So, substituting the given points into the given inequalities, we have:

- A. (2,1)

Substituting into the first inequality, we have:

y\leq 2x-2\\\\1\leq 2*(2)-2\\\\1\leq 4-2\\\\1\leq 2

Substituting into the second inequality, we have:

y\leq x^{2} -3x

1\leq (2)^{2} -3(2)

1\leq (2)^{2} -3(2)

1\leq 4 -6

1\leq -2

Therefore, since 1 is not less or equal to -2, the point A(2,1) is not a solution to the system of inequalities.

- B. (-2,-1)

Substituting into the first inequality, we have:

y\leq 2x-2\\\\-1\leq (-2)*(2)-2\\\\-1\leq -4-2\\\\-1\leq -6

Substituting into the second inequality, we have:

y\leq x^{2} -3x

-1\leq (-2)^{2} -3(-2)

-1\leq 4 +6

-1\leq 10

Therefore, since -1 is not less or equal to -6, the point B(-2,-1) is not a solution to the system of inequalities.

- C. (4,2)

Substituting into the first inequality, we have:

y\leq 2x-2\\\\2\leq (4)*(2)-2\\\\2\leq 8-2\\\\2\leq 6

Substituting into the second inequality, we have:

y\leq x^{2} -3x

2\leq (4)^{2} -3(4)

2\leq 16 -12

2\leq 4

Therefore, since 2 is less than 6, and 2 is less than 4, the point B(4,2) is a solution to the system of inequalities.

- D(1,3)

Substituting into the first inequality, we have:

y\leq 2x-2\\\\3\leq (1)*(2)-2\\\\3\leq 2-2\\\\3\leq 0

Substituting into the second inequality, we have:

y\leq x^{2} -3x

3\leq (1)^{2} -3(1)

3\leq 1 -3

3\leq -2

Therefore, since 3 is not less than 0, and 3 is not less than -2, the point D(1.3) is not a solution to the system of inequalities.

Hence, the point that is a solution to the system of inequalities is C(4,2).

Have a nice day!

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