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Svetllana [295]
3 years ago
9

Please helppp I need every problem to be done

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
4 0

Answer:

a. two thousand

b. 6043

c. (8 x 10,000) + (5 x 1,000) + (0 x 000) + (2 x 10)

d. 10205041500

e. thirty hundred sixty million, twenty-five thousand, one hundred three

1. c

2. 334,333

3. 3,666,766

4. 39,959,992

5. 41,200,000,520

I hope this helps any.

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6 + 3x = 2(2 + x)<br><br> What is this answer I need help please anytime soon
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6+3x = 2(2 + x)

First we will need to open the parenthesis by multiplying the number that’s in front of them:

6+3x=4+2x

Now we need to separate the numbers from the X. By subtracting 2x from both sides:

6+3x=4+2x
-2x -2x
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6+x=4

Now we subtract 6 from both sides.

6+x=4
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X = -2
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3 years ago
What is the volume of the oblique cube
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Answer:

\large\boxed{V=\dfrac{1600\pi}{3}\ cm^3}

Step-by-step explanation:

The formula of a volume of a cone:

V=\dfrac{1}{3}\pi r^2H

r - radius

H - height

We have r = 10cm and H = 16cm. Substitute:

V=\dfrac{1}{3}\pi(10^2)(16)=\dfrac{1}{3}\pi(100)(16)=\dfrac{1600\pi}{3}\ cm^3

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Part A: Find a rational number that is between 9.5 and 9.7. Explain why it is rational. (2 points)
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Answer:

  A. 9.6

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Step-by-step explanation:

<h3>A.</h3>

Rational: 9.6. It is rational because it is a terminating decimal number.

__

<h3>B.</h3>

Irrational: √92 ≈ 9.59166.... It is irrational because it is the square root of an integer that is not a perfect square. All such square roots are irrational.

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<em>Additional comment</em>

In general, the n-th root of an integer that is not a perfect n-th power will be irrational. For example, ∛885 ≈ 9.600954766... is irrational, because 885 is not a perfect cube. (9³=729, 10³=1000)

Trig functions of (non-zero) rational angles in radians will be irrational. For example, tan(1.467) ≈ 9.5996286... is irrational.

3 0
3 years ago
The height, h, in feet of the tip of the hour hand of a wall clock varies from 9 feet to 10 feet. Which of the following equatio
bixtya [17]

The correct option is (b) h=0.5cos(\pi/6t)+9.5.

The equations can be used to model the height as a function of time, t, in hours is h=0.5cos(\pi/6t)+9.5.

<h3>Equation of cosine function:</h3>

The following is a presentation of the cosine function's generic form;

y =  a + cos(bx - c) + d

amplitude = a

b = cycle speed

Calculation for the model height;

The height, h (feet) of the tip of the hour hand of a wall clock varies from 9 feet to 10 feet.

Obtain amplitude 'a' as

\begin{aligned}a &=\frac{\text { Maximum value }-\text { Minimum value }}{2} \\a &=\frac{10-9}{2} \\a &=\frac{1}{2} \\a &=0.5\end{aligned}

The time 'T' is calculated as-

\begin{aligned}&\mathrm{T}=\frac{2 \pi}{\mathrm{b}} \\&12=\frac{2 \pi}{\mathrm{b}} \\&\mathrm{b}=\frac{2 \pi}{12} \\&\mathrm{~b}=\frac{\pi}{6}\end{aligned}

Now, calculate 'd'

\begin{aligned}&\mathrm{d}=\frac{\text { Maximum value }+\text { Minimum value }}{2} \\&\mathrm{~d}=\frac{10+9}{2} \\&\mathrm{~d}=\frac{19}{2} \\&\mathrm{~d}=9.5\end{aligned}

Therefore, with the height as a function of time, t, expressed in hours, can be modeled by the following equations:

h=0.5cos(\pi/6t)+9.5

To know more about the general equation of a cosine function, here

brainly.com/question/27587720

#SPJ4

The complete question is-

The height, h, in feet of the tip of the hour hand of a wall clock varies from 9 feet to 10 feet. Which of the following equations can be used to model the height as a function of time, t, in hours? Assume that the time at t = 0 is 12:00 a.m.

A. h=0.5cos(\pi/12t)+9.5

B. h=0.5cos(\pi/6t)+9.5

C. h=cos(\pi/12t)+9

D. h=cos(\pi/6t)+9

7 0
2 years ago
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