U.S. citizens are guaranteed free access to which level of education?
2 answers:
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Answer:
Explanation:
Given
x is a factor
Required
Solve for k
x is a factor means that the polynomial can be divided successfully by x.
In other words, x is a zero of the polynomial.
i.e.
and
Substitute 0 for x in P(x)
Substitute 0 for P(x)
Collect Like Terms
Divide both sides by 5
Answer:
a. 99.30% of the woman meet the height requirement
b. If all women are eligible except the shortest 1% and the tallest 2%, then height should be between 58.32 and 68.83
Explanation:
<em>According to the survey</em>, women's heights are normally distributed with mean 63.9 and standard deviation 2.4
a)
A branch of the military requires women's heights to be between 58 in and 80 in. We need to find the probabilities that heights fall between 58 in and 80 in in this distribution. We need to find z-scores of the values 58 in and 80 in. Z-score shows how many standard deviations far are the values from the mean. Therefore they subtracted from the mean and divided by the standard deviation:
z-score of 58 in= = -2.458
z-score of 80 in= = 6.708
In normal distribution 99.3% of the values have higher z-score than -2.458
0% of the values have higher z-score than 6.708. Therefore 99.3% of the woman meet the height requirement.
b)
To find the height requirement so that all women are eligible except the shortest 1% and the tallest 2%, we need to find the boundary z-score of the
shortest 1% and the tallest 2%. Thus, upper bound for z-score has to be 2.054 and lower bound is -2.326
Corresponding heights (H) can be found using the formula
and
Thus lower bound for height is 58.32 and
Upper bound for height is 68.83
The standard error of the difference of sample means is 0.444
From the complete question, we have the following parameters
<u>Canadians</u>
- Sample size = 50
- Mean = 4.6
- Standard deviation = 2.9
<u>Americans</u>
- Sample size = 60
- Mean = 5.2
- Standard deviation = 1.3
The standard error of a sample is the quotient of the standard deviation and the square root of the sample size.
This is represented as:
The standard error of the Canadian sample is:
So, we have:
The standard error of the American sample is:
So, we have:
The standard error of the difference of sample means is then calculated as:
This gives
Take square roots
Hence, the standard error of the difference of sample means is 0.444
Read more about standard errors at: