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NikAS [45]
3 years ago
13

How do you solve for x in the equation 4x-2(x-2)=-9+5x-8

Mathematics
1 answer:
elixir [45]3 years ago
5 0

first distribute the 2 into (x-2) so that the new equation is 4x-2x+4=9+5x-8 Afterwards add up common factors and get the x to one side 2x+4=1+5x (subtract 2x from both sides) 4=1+3x (subtract 1 from both sides) 3=3x (divide by 3 on both sides) 1=x

Hope this helped!!

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A quantity with an initial value of 6200 decays continuously at a rate of 5.5% per month. What is the value of the quantity afte
ELEN [110]

Answer:

410.32

Step-by-step explanation:

Given that the initial quantity, Q= 6200

Decay rate, r = 5.5% per month

So, the value of quantity after 1 month, q_1 = Q- r \times Q

q_1 = Q(1-r)\cdots(i)

The value of quantity after 2 months, q_2 = q_1- r \times q_1

q_2 = q_1(1-r)

From equation (i)

q_2=Q(1-r)(1-r)  \\\\q_2=Q(1-r)^2\cdots(ii)

The value of quantity after 3 months, q_3 = q_2- r \times q_2

q_3 = q_2(1-r)

From equation (ii)

q_3=Q(1-r)^2(1-r)

q_3=Q(1-r)^3

Similarly, the value of quantity after n months,

q_n= Q(1- r)^n

As 4 years = 48 months, so puttion n=48 to get the value of quantity after 4 years, we have,

q_{48}=Q(1-r)^{48}

Putting Q=6200 and r=5.5%=0.055, we have

q_{48}=6200(1-0.055)^{48} \\\\q_{48}=410.32

Hence, the value of quantity after 4 years is 410.32.

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You have checked model income statements and estimate your payroll expense will be 36% of revenue. You expect sales to be $9,000
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Answer:

Budget annual payroll = $168,480

Step-by-step explanation:

Given:

Expect sales per week = $9,000

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Budget annual payroll = ?

Computation:

Assume number of week per year = 52

⇒ Budget annual payroll =  Expect sales per week × Number of week per year × Revenue over sales

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3 0
3 years ago
Find the value of A if the 4-digit number 3A5A is divisible by both 3 and 5.
Arturiano [62]

Answer:

The value of A is 5

Step-by-step explanation:

- The number is divisible by 3 if the sum of its digits is a number

  divisible by 3

- Ex: 126 is divisible by 3 because the sum of its digits = 1 + 2 + 3 = 6

  and 6 is divisible by 3

- The number is divisible by 5 if its ones digit is zero or 5

- Ex: 675 is divisible by 5 because its ones digit is 5

        890 is divisible by 5 because its ones digit is 0

- We are looking for the value of A in the 4-digit number 3A5A which

  makes the number divisible by both 3 and 5

∵ A is in the ones position

∴ A must be zero or 5

- Let us try A = 0

∵ A = 0

∴ The number is 3050

∵ The sum of the digits of the number = 3 + 0 + 5 + 0 = 8

∵ 8 is not divisible by 3

∴ 3050 is not divisible by both 3 and 5

∴ A can not be zero

- Let us try A = 5

∵ A = 5

∴ The number is 3555

∵ The sum of the digits of the number = 3 + 5 + 5 + 5 = 18

∵ 18 is divisible by 3

∴ 3555 is divisible by both 3 and 5

∴ A must be equal 5

* <em>The value of A is 5</em>

5 0
3 years ago
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