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3 years ago

Which equation, when graphed, has x-intercepts at (2, 0) and (4, 0) and a y-intercept of (0, –16)?

Mathematics

2 answers:

Katena32 [7]3 years ago

7 0

Answer:

f(x) = –2(x – 2)(x – 4)

Step-by-step explanation:

wlad13 [49]3 years ago

5 0

The zeros are 2 and 4, so obviously either A or C, (eliminate B and D which have zeros of -2 and -4.)
the y intercept is -16. Plug x=0 in A and C to see which equation produce a result -16. C is correct.

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Need hep wit this thx

PSYCHO15rus [73]

Answer:

answer is 3

Step-by-step explanation:

n+1=3+2/2=3

The number is 3 and it is a odd number.

I hope it's helpful!

4 0

3 years ago

Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th

grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{6}$

$P(1) = \frac{1}{3}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{6}$

$P(2) = \frac{1}{2}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

7 0

2 years ago

What is the quotient of 5 1/2 and 1/8

Stels [109]

Answer:

Step-by-step explanation:

5 1/2 / 1/8

turn into improper fraction

11/2 then change to multiplication

11/2*8/1(have to flip)

88/2(multiply across)

simplify=44

4 0

3 years ago

URGENT MATH HELP BRAINLIEST

Lelechka [254]

Answer:

Step-by-step explanation:

a. This is a right triangle with two sides and one angle given.

-We apply Sine Rule to find the angle B:

$\frac{a}{Sin \ A}=\frac{b}{Sin \ B}=\frac{b}{Sin \ C}$

-The sides given are 10and 17 and the right angle 90°

$\frac{17}{Sin \ 90 \textdegree}=\frac{10}{Sin \ m\angle B}\\\\m\angle B=Sin^{-1}\frac{10}{(17/Sin \ 90\textdegree)}\\\\=36.03\textdegree$

Hence the angle B is 36.03°

b.We again use the sine rule to obtain the unknown angle w:

-15 corresponds to 90° and 9 corresponds to w°

$\frac{a}{Sin \ a}=\frac{b}{Sin \ B}\\\\\frac{15}{Sin \ 90\textdegree}=\frac{9}{Sin \ w\textdegree}\\\\\\\\w=Sin^{-1}(\frac{9}{15}), \ \ Sin \ 90\textdegree=1\\\\=36.87\textdegree$

Hence, the measure of w is 36.87°

4 0

2 years ago

What is the difference between the sum of the first 2003 even counting numbers and the sum of the first 2003 odd counting number

Lana71 [14]

The difference is 2003.

The formula for the sum of the first n even numbers is SE = n^{2} + n, (E standing for even).

The sum of the first n odd numbers is SO = n^{2}, (O standing for odd).

Knowing this, plug 2003 for n,

SE - SO= (2003^{2} + 2003) - (2003^{2}) = 2003

The difference is 2003.

A number that can be divided into two halves, i.e. into two equal parts is called an even number. Even numbers are exactly divisible by 2 which means the remainder will be 0.

Learn more about Even numbers here: brainly.com/question/251701

#SPJ4

7 0

2 years ago