Answer:
the answer should be 30
Step-by-step explanation:
since you can divided 15 by 5 to get 3, you can multiply 10 x 3 to get 30
Answer:
(x + 39) or x = -39
Step-by-step explanation:
Set f(x) to 0
0 = 5x + 195
5x = -195
x = -39
Answer:
a) P(Y > 76) = 0.0122
b) i) P(both of them will be more than 76 inches tall) = 0.00015
ii) P(Y > 76) = 0.0007
Step-by-step explanation:
Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.
To find - (a) If a man is chosen at random from the population, find
the probability that he will be more than 76 inches tall.
(b) If two men are chosen at random from the population, find
the probability that
(i) both of them will be more than 76 inches tall;
(ii) their mean height will be more than 76 inches.
Proof -
a)
P(Y > 76) = P(Y - mean > 76 - mean)
= P(
) >
)
= P(Z >
)
= P(Z >
)
= P(Z > 2.25)
= 1 - P(Z ≤ 2.25)
= 0.0122
⇒P(Y > 76) = 0.0122
b)
(i)
P(both of them will be more than 76 inches tall) = (0.0122)²
= 0.00015
⇒P(both of them will be more than 76 inches tall) = 0.00015
(ii)
Given that,
Mean = 69.7,
= 1.979899,
Now,
P(Y > 76) = P(Y - mean > 76 - mean)
= P(
)) >
)
= P(Z >
)
= P(Z >
))
= P(Z > 3.182)
= 1 - P(Z ≤ 3.182)
= 0.0007
⇒P(Y > 76) = 0.0007
You multiply 3x - y = 3.
So then it's:
6x - 2y = 3
-2x + 2y =6
which equals 4x = 9
An outlier is a datapoint outside of the first or third quartile +/- 1.5 the inter quartile range
25 33 39 40 41 41 45 46 48 49 51 52 67 73 79
46 is at the center-> median
everything left of it:
25 33 39 40 41 41 45
40 at center=Q1
right of Q2:
48 49 51 52 67 73 79
52 at center=Q3
IQR=Q3-Q1=52-40=12
Q1-1.5*IQR=40-1.5*12=40-18=22
Q3+1.5*IQR=52+1.5*12=52+18=60
so everything <22 or >60 are outliers
so 67,73 and 79 are outliers