Let that be

Two vertical asymptotes at -1 and 0

If we simply

- Denominator has degree 2
- Numerator should have degree as 2 and coefficient as 3 inorder to get horizontal asymptote y=3 means the quadratic equation should contain 3x²
- But there should be a x intercept at -3 so one zeros should be -3
Find a equation
Find zeros
Horizontal asymptote
So our equation is

Graph attached
Answer:
D.
Step-by-step explanation:
Be:
Number of hours: n
<span>The cost of renting a bike for the first hour is $7:
n=1→f(n)=f(1)=$7
</span>He is charged $2.50 for every additional hour of renting the bike:
f(n)=f(n-1)+2.50, for <span>n ≥ 2
</span>
f(1)=7; f(n)=f(n-1)+2.50, for <span>n ≥ 2 (sixth option)
</span>
f(n)=f(1)+2.50(n-1)
f(n)=7+2.50(n-1)
f(n)=7+2.50n-2.50
f(n)=2.50n+4.50 (fifth option)
Answers:
Fifth option: f(n)=2.50n+4.50, and
Sixth option: f(1)=7; f(n)=f(n-1)+2.50, for <span>n ≥ 2</span>
Answer:allison
Step-by-step explanation: