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Vsevolod [243]
3 years ago
6

Find the distance between the given points (2,8) and (7,7)

Mathematics
1 answer:
Ray Of Light [21]3 years ago
6 0

Answer:

d=\sqrt{26}\approx5.0990

Step-by-step explanation:

To find the distance between any two points, we can use the distance formula.

The distance formula is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Let (2,8) be x₁ and y₁ and let (7,7) be x₂ and y₂. Thus:

d=\sqrt{(7-2)^2+(7-8)^2}

Simplify:

d=\sqrt{5^2+(-1)^2}

Square:

d=\sqrt{25+1}

Add:

d=\sqrt{26}\approx5.0990

And that's our answer :)

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Could someone help me please
Rina8888 [55]

Answer:

the answer should be 30

Step-by-step explanation:

since you can divided 15 by 5 to get 3, you can multiply 10 x 3 to get 30

8 0
3 years ago
Find the zero of: f(x)=5x+195
monitta

Answer:

(x + 39) or x = -39

Step-by-step explanation:

Set f(x) to 0

0 = 5x + 195

5x = -195

x = -39

4 0
2 years ago
The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.
Mama L [17]

Answer:

a) P(Y > 76) = 0.0122

b) i) P(both of them will be more than 76 inches tall) = 0.00015

   ii) P(Y > 76) = 0.0007

Step-by-step explanation:

Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.

To find - (a) If a man is chosen at random from the population, find

                    the probability that he will be more than 76 inches tall.

              (b) If two men are chosen at random from the population, find

                    the probability that

                    (i) both of them will be more than 76 inches tall;

                    (ii) their mean height will be more than 76 inches.

Proof -

a)

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{S.D}) > \frac{( 76- mean)}{S.D})

                 = P(Z >  \frac{( 76- mean)}{S.D})

                 = P(Z > \frac{76 - 69.7}{2.8})

                 = P(Z > 2.25)

                 = 1 - P(Z  ≤ 2.25)

                 = 0.0122

⇒P(Y > 76) = 0.0122

b)

(i)

P(both of them will be more than 76 inches tall) = (0.0122)²

                                                                           = 0.00015

⇒P(both of them will be more than 76 inches tall) = 0.00015

(ii)

Given that,

Mean = 69.7,

\frac{S.D}{\sqrt{N} } = 1.979899,

Now,

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{\frac{S.D}{\sqrt{N} } })) > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- 69.7)}{1.979899 }))

                 = P(Z > 3.182)

                 = 1 - P(Z ≤ 3.182)

                 = 0.0007

⇒P(Y > 76) = 0.0007

6 0
3 years ago
To solve this system using the addition method, you would need to multiply the first equation by what number in order for the y'
yanalaym [24]
You multiply 3x - y = 3.
So then it's:
6x - 2y = 3
-2x + 2y =6

which equals 4x = 9
8 0
3 years ago
Here are the prices, rounded to the nearest dollar, of the most frequently purchased gifts in a gift store.
Mariulka [41]
An outlier is a datapoint outside of the first or third quartile +/- 1.5 the inter quartile range

25 33 39 40 41 41 45 46 48 49 51 52 67 73 79

46 is at the center-> median
everything left of it:
25 33 39 40 41 41 45
40 at center=Q1
right of Q2:
48 49 51 52 67 73 79
52 at center=Q3

IQR=Q3-Q1=52-40=12

Q1-1.5*IQR=40-1.5*12=40-18=22
Q3+1.5*IQR=52+1.5*12=52+18=60

so everything <22 or >60 are outliers

so 67,73 and 79 are outliers
4 0
3 years ago
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