Answer:
D
Step-by-step explanation:
Summarizing the question,
Principle(P)=$100
Rate (r)=12%=0.12
Amount (A)=3×P=$300
Time=t=?
n=no of times the interest is compouned per year=4
Then,
A=P{(1+r/n)}^(n×t)
or,300=100×{1+0.12/4}^(4×t)
or,300/100=(1+0.03)^(4×t)
or,3=1.03^(4×t)
Taking log on both sides,
log3=log[(1.03)^(4×t)]
or,log3= (4×t)×log(1.03)
or,4t=log3/log(1.03)
or,t=log3/[4×log(1.03)]
or, t=9.29175...
t=9.3 years ANS!!!
Answer:
b. Determine the number of homozygous dominant alleles for red eyes
Step-by-step explanation:
Answer:
The interest is equal to \$13$13
we know that
The compound interest formula is equal to
A=P(1+\frac{r}{n})^{nt}A=P(1+
n
r
)
nt
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
\begin{gathered}t=3\ years\\ P=\$80\\ r=0.05\\n=1\end{gathered}
t=3 years
P=$80
r=0.05
n=1
substitute in the formula above
A=\$80(1+\frac{0.05}{1})^{3}=\$92.61A=$80(1+
1
0.05
)
3
=$92.61
Find the interest
I=A-P=\$92.61-\$80=\$12.61I=A−P=$92.61−$80=$12.61
Round to the nearest whole dollar
\$12.61=\$13$12.61=$13
Answer:
the answer is 5ft wide
Step-by-step explanation:
Hope this helps!
