First, we find the slope of the given line.
<span>3x − 4y = 7
-4y = -3x + 7
y = (3/4)x - 7/4
The slope of the given line is 3/4.
The slope of the parallel line is also 3/4.
Now we need the equation of the line that has slope 3/4 and passes through point (-4, -2),
We use the point-slope form of the equation of a line.
y - y1 = m(x - x1)
y - (-2) = (3/4)(x - (-4))
y + 2 = (3/4)(x + 4) <---- check option E. Is the fraction 3/4 not there?
y + 2 = (3/4)x + 3
y = (3/4)x + 1
4y = 3x + 4
3x - 4y = -4 <------ this is choice B.
</span>
Answer:
117
Step-by-step explanation:
I think its 4 because the lines intersect 4 times but its been too long since ive done nonlinear equations
Answer:
450
Step-by-step explanation:
first off, let's notice the parabola is a vertical one, therefore the squared variable is the x, and the parabola is opening upwards, meaning the coefficient of x² is positive.
let's notice the vertex, or U-turn, is at (-2, 2)
![\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \boxed{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{-2}{ h},\stackrel{2}{ k}) \\\\\\ y=+1[x-(-2)]^2+2\implies y=(x+2)^2+2](https://tex.z-dn.net/?f=%20%5Cbf%20~~~~~~%5Ctextit%7Bparabola%20vertex%20form%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%20%5Cboxed%7By%3Da%28x-%20h%29%5E2%2B%20k%7D%5C%5C%5C%5C%20x%3Da%28y-%20k%29%5E2%2B%20h%20%5Cend%7Barray%7D%20%5Cqquad%5Cqquad%20vertex~~%28%5Cstackrel%7B-2%7D%7B%20h%7D%2C%5Cstackrel%7B2%7D%7B%20k%7D%29%20%5C%5C%5C%5C%5C%5C%20y%3D%2B1%5Bx-%28-2%29%5D%5E2%2B2%5Cimplies%20y%3D%28x%2B2%29%5E2%2B2%20)
