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Alina [70]
4 years ago
10

Is this a bad CPU chip I need help asapppppp

Computers and Technology
1 answer:
rusak2 [61]4 years ago
8 0

Answer:

Potentially bad.

Explanation:

It appears that on the CPU, there are bent pins.  From the picture perspective, these are on the far right of the CPU and near the bottom left.  Bent CPU pins can potentially be repositioned, but more than likely will break.  When pins break, the CPU will no longer work as intended as the chipset will not be able to make the assumed calls to those pins on the CPU.  If this is a new chip, and you didn't cause this damage, you should RMA the CPU back to the vendor you bought it from.

Cheers.

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Read 2 more answers
Question is attached as image, please help :&gt;
harkovskaia [24]

Answer:

Proved

Explanation:

Given

X = (a.\bar b)+(\bar a.b)

(a + b)\ .  \frac{}{a.b}

Required

Find out why they represent the same

To do this, we simplify either (a + b)\ .  \frac{}{a.b} or X = (a.\bar b)+(\bar a.b)

In this question, I will simplify (a + b)\ .  \frac{}{a.b}

Apply de morgan's law

(a + b)\ .  \frac{}{a.b} = (a + b) . (\bar a + \bar b)

Apply distribution property

(a + b)\ .  \frac{}{a.b} = a.\bar a + a.\bar b + \bar a . b + b . \bar b

To simplify, we apply the following rules:

a.\bar a = 0 --- Inverse law

b.\bar b = 0 --- Inverse law

So, the expression becomes

(a + b)\ .  \frac{}{a.b} = 0 + a.\bar b + \bar a.b + 0

(a + b)\ .  \frac{}{a.b}  = a.\bar b + \bar a.b

Rewrite as:

(a + b)\ .  \frac{}{a.b}  = (a.\bar b)+(\bar a.b)

From the given parameters:

X = (a.\bar b)+(\bar a.b)

This implies that:

(a + b)\ .  \frac{}{a.b} when simplified is X or (a.\bar b)+(\bar a.b)

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