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Umnica [9.8K]
3 years ago
7

Rewrite using only positive exponents.

20%7B%7D%5E%7B2%7D%20%7D%20" id="TexFormula1" title=" \frac{1}{3a ^{ - 1} b {}^{2} } " alt=" \frac{1}{3a ^{ - 1} b {}^{2} } " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Komok [63]3 years ago
6 0
That would be  a / 3b^2


(re call that 1 /a^-1  = a)
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Casper bought some pencils at .50 each. He had $3 left after the purchase. If he wanted to buy the same number of note pads at .
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<u>Answer:   </u>

Required linear equation to get number of pencils purchased by Casper is 3x – 45 = 0 where x represents number of pencils and number of pencils Casper purchased = 15.

<u>Solution: </u>

Let’s assume number of pencils purchased by Casper = x

As given price of each pencil is 0.50 , so price of x pencils = 0.50x = 0.5x

Also given that she was left with $3 after buying x pencils.

So initial amount which was with casper = price of x pencils + amount he was left with.

=> Initial amount with Casper = 0.5x + 3    ------(1)

Now consider second scenario  

If Casper wanted to buy same number of notepad at price of 0.80 each , then

Total amount need for x notepad = 0.80x = 0.8x

But its also given that he will be short of $1.5.

So initial amount with Casper = 0.80x – 1.5 ------(2)

On equating initial amount with casper using equation (1) and equation(2) we get

0.5x + 3 = 0.8x – 1.5

=> 0.8x – 0.5x = 3 + 1.5

=> 0.3x = 4.5

=> 0.3x – 4.5 = 0  

=> 3x – 45 = 0

So linear equation for x that is number of pencils he purchased is 3x – 45 = 0 where variable x represents number of pencils.

On solving the linear equation 3x – 45 = 0 for x we get

3x = 45

x = 15

Hence required linear equation to get number of pencils purchased by Casper is 3x – 45 = 0 where x represents number of pencils and number of pencils Casper purchased = 15.

7 0
3 years ago
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