Answer:
An Inverse variation states that a relationship between two variables in which the product is always constant.
If one of the variable increases then the other decreases in proportion so that the product is unchanged.
if y is inversely proportional to x, then the equation is of the form
, where k is constant.
As per the given condition, A constant force acts upon an object, the acceleration of the object varies inversely with it's mass.
i.e, 
By definition of inverse variation;
. ......[1] ,where F is the constant force.
It is given that an object has mass(m)= 4kg and the acceleration of an object(a) = 14 
Substitute these in [1] to find the constant force F;

or

Now, if the same force acts upon the another object whose mass (m) = 7 kg then calculate acceleration.
[1]⇒ 
therefore, the acceleration of an another object is, 