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Alenkasestr [34]
3 years ago
5

Please help me it’s really important for me

Mathematics
1 answer:
viva [34]3 years ago
4 0

Answer:

idk, so sorry, Google it

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- 2 + 0.8) ÷ (- 1.3) =<br><img src="https://tex.z-dn.net/?f=%20%28%20-%202%20%2B%200.8%29%20%5Cdiv%20%28%201%7D%5E%7B2%7D%20%20-
Nookie1986 [14]
(-2 + 0.8) ÷ (1²-1.3) =

(-1.2) ÷ (1-1.3)

(-1.2) ÷ (-0.3)

= 4
6 0
3 years ago
Write the function in standard form <br><br> F(x)=-3(x-6)^2+15
LenKa [72]

Answer:

(6,15)

Step-by-step explanation:

7 0
3 years ago
What operations are needed to solve this word problem? Joe has 8 Dalmatians. Sarah has 3 fewer Dalmatians than Joe. How many Dal
yan [13]
You take it like this=

8
-3
~~
3
+
3
+
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~~
(4×2)
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[[5]]

《5+8》


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3 0
3 years ago
Any help would be appreciated! :)
ikadub [295]

Answer:

-7, then -13, then -19

Step-by-step explanation:

Plug in x values to get y.

y = -2(0) - 7

y = 0 - 7

y = -7

y = -2(3) - 7

y = -6 - 7

y = -13

y = -2(6) - 7

y = -12 - 7

y = -19

Hope this helps. :0)

7 0
2 years ago
Read 2 more answers
In a certain computer, the probability of a memory failure is 0.01, while the probability of a hard disk failure is 0.02. If the
ratelena [41]

Answer:

We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:

P(A \cap B) = P(A) *P(B)

For this case we have that:

P(A) *P(B) = 0.01*0.02= 0.0002

And we see that 0.0002 \neq P(A \cap B)

So then we can conclude that the two events given are not independent and have a relationship or dependence.

Step-by-step explanation:

For this case we can define the following events:

A= In a certain computer a memory failure

B= In a certain computer a hard disk failure

We have the probability for the two events given on this case:

P(A) = 0.01 , P(B) = 0.02

We also know the probability that the memory and the hard drive fail simultaneously given by:

P(A \cap B) = 0.0014

And we want to check if the two events are independent.

We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:

P(A \cap B) = P(A) *P(B)

For this case we have that:

P(A) *P(B) = 0.01*0.02= 0.0002

And we see that 0.0002 \neq P(A \cap B)

So then we can conclude that the two events given are not independent and have a relationship or dependence.

8 0
3 years ago
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