Multiply. Express your answer in simplest form. 5/8, 24
2 answers:
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Let 
, where
and let
be any real constant.
Given this definition of scalar multiplication, we can see right away that there is no identity element
such that
because
and let
Given this definition of scalar multiplication, we can see right away that there is no identity element
because
x² - x - 12 ≠ 0
x² - 4x + 3x - 12 ≠ 0
x (x - 4) + 3 (x - 4) ≠ 0
(x + 3)(x - 4) ≠ 0
x ≠ -3 or x ≠ 4
(B)