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Natasha2012 [34]
3 years ago
7

Whoever gets it right ill reward brainlyess answer

Mathematics
2 answers:
zepelin [54]3 years ago
8 0
1. Set up a proportion:
18/1:90/x
2. Cross multiply:
18x=90
3. Solve:
90/18=5
5 hours
irga5000 [103]3 years ago
4 0
The correct answer is 5h
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April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3
vlada-n [284]

Answer:

        Student                                                            Hours worked

             April.                                                                  7\frac{7}{8} \ hrs

        Debbie.                                                                   8\frac{1}{8}\ hrs

        Richard.                                                                   7\frac{19}{24}\ hrs

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = 5\frac{1}{4}\ hrs

5\frac{1}{4}\ hrs can be Rewritten as \frac{21}{4}\ hrs

Number of Hours Carl worked on Math project = \frac{21}{4}\ hrs

Number of Hours Sonia worked on Math project = 6\frac{1}{2}\ hrs

6\frac{1}{2}\ hrs can be rewritten as \frac{13}{2}\ hrs

Number of Hours Sonia worked on Math project = \frac{13}{2}\ hrs

Number of Hours Tony worked on Math project = 5\frac{2}{3}\ hrs

5\frac{2}{3}\ hrs can be rewritten as \frac{17}{3}\ hrs.

Number of Hours Tony worked on Math project = \frac{17}{3}\ hrs.

Now Given:

April worked 1\frac{1}{2} times as long on her math project as did Carl.

1\frac{1}{2}  can be Rewritten as \frac{3}{2}

Number of Hours April worked on math project = \frac{3}{2} \times Number of Hours Carl worked on Math project

Number of Hours April worked on math project = \frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs

Also Given:

Debbie worked 1\frac{1}{4} times as long as Sonia.

1\frac{1}{4}  can be Rewritten as \frac{5}{4}.

Number of Hours Debbie worked on math project = \frac{5}{4} \times Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = \frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs

Also Given:

Richard worked 1\frac{3}{8} times as long as tony.

1\frac{3}{8} can be Rewritten as \frac{11}{8}

Number of Hours Richard worked on math project = \frac{11}{8} \times Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = \frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs

Hence We will match each student with number of hours she worked.

        Student                                                            Hours worked

             April.                                                                  7\frac{7}{8} \ hrs

        Debbie.                                                                   8\frac{1}{8}\ hrs

        Richard.                                                                   7\frac{19}{24}\ hrs

5 0
3 years ago
Read 2 more answers
A function is shown in the table below. What equation represents this function?
den301095 [7]

Answer:

y=-3x+6

Step-by-step explanation:

that equation gives the answer for all the 'y'

7 0
3 years ago
Please answer asap brainset
drek231 [11]

Answer:

9 and 3

Step-by-step explanation:

9 feet. 12 inches = 1 foot. 3 feet = 1 yard.

4 0
3 years ago
The measure of ∠AKG is 133°.
denis23 [38]
Mes ∠AKG = mes ∠AKD + mes ∠ DKG
 
133° = mes ∠ AKD + 87°

133° - 87° = mes ∠AKD

∠AKD = 46°

7 0
3 years ago
Lisa and Julia are selling cookie dough for a school fundraiser. Customers can buy packages of sugar cookie dough and packages o
MrRissso [65]

Answer:

x=12...................Cost of one package of sugar cookie dough =$12

y=16...................Cost of chocolate chip cookie dough=$16

Step-by-step explanation:

The question is on formation of simultaneous equations

Let Sugar cookie dough to be x

Let chocolate chip cookie dough to be y

Equations

Lisa--------13x + 6y = $252------------------(a)

Julia-------8x + 12 y= $288------------------(b)

Solving the equations

12(13x + 6y = 252)----------------156x +72y=3024

6(8x + 12 y= 288)------------------48x + 72y=1728

Eliminate 72y by subtraction

108x=1296---------------------divide both sides by 108 to remain with x

x=1296/108-------x=12-------------------(c)

substitute (c) in (a) above

13x + 6y = 252

(13×12)+ 6y =252

156+6y=252

6y=252-156

6y=96--------------------divide both sides by 6 to remain with y

y=96/6 =16

Solutions

x=12...................Cost of one package of sugar cookie dough =$12

y=16...................Cost of chocolate chip cookie dough=$16

5 0
3 years ago
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