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qwelly [4]
2 years ago
15

Who can help with this

Mathematics
1 answer:
vagabundo [1.1K]2 years ago
7 0

GiveN:

  • ABCD is a parallelogram.
  • AC and BD are the diagonals.
  • DE = 28 units

To FinD:

  • Value of x in length of BE?

Step-wise-Step Explanation:

We know that,

In any parallelogram, the diagonals (lines linking opposite corners) bisect each other. Then, AE = EC for diagonal AC and BE = DE for diagonal BD.

⇒ BE = DE

⇒ x - 4 = 28 units

⇒ x = 32 units

Hence, The required value of x here is <u>3</u><u>2</u><u> </u><u>units</u><u>.</u>

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A family swimming pool membership costs $27.50 per month plus a one-time registration fee of $25. If a family has paid a total o
Anna [14]

Answer:

5 months

Step-by-step explanation:

y=mx+b

162.50=27.50x+25

162.50-25=27.50x+25-25

137.50=27.50x

137.50/27.50=x

5=x

hope this helps :)

8 0
3 years ago
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Zack has a old car. He wants to sell it for 60% off the current price. The market price is $500. How much money would he receive
Snowcat [4.5K]
Zack would receive $200. You have to make 60% as a decimal= 0.60 then multiply $500*0.60= $300 then you subtract $500-$300=$200
(Hope this works!!)
6 0
3 years ago
Solve for y in terms of x
AnnZ [28]
-8x+ 4y= -16
4y= 8x - 16
divide it by 4
y= 2x -4
if x is 0 what is y?
y = 2 (0)-4
y = 4
just put an x value in the equation u will get your y value

1 (0,4)
2 (1,-2)
3 (2,0)
4 (3,2)
5 (4,4)
7 0
3 years ago
Lori has 12 1/2 pounds of flour. She needs 1 3/4
12345 [234]
She can make 7 1/7 batches of cookies :)
4 0
2 years ago
Plz helpppppppp meeeeeeeeee
Tems11 [23]

Answer:

Event 4, Event 2, Event, 3, Event 1

Step-by-step explanation:

An easy way to solve this problem is to calculate the probability of each event in this problem occurring. After doing so, one can compare the probability as a percent value and then order them from least to greatest. Remember, probability can be described as the following,

\frac{desired\ outcomes}{possible\ outcomes}

In this case, the equation would be written as the following,

\frac{type \ of\ marble}{total\ marbles}

<u>Given</u>

Bag A -> 9 green marbles, 11 white marbles

Bag B -> 8 green marbles, 8 white marbles

Event 1- Picking a green or white marble from Bag A.

Since there are only green and white marbles in Bag (A), there is a (100%) chance of this event happening, since there are only green and white marbles in this bag.

Event 2- Choosing a green marble from Bag A.

To solve this probability, one will need to put the number of green marbles over the total number of marbles, then convert the fraction into percent form.

\frac{green}{green+white}\\

Substitute,

\frac{9}{9+11}\\\\=\frac{9}{20}

Multiply by (5) to make the denominator (100) and convert to a percent,

\frac{9}{20}*\frac{5}{5}\\=\frac{45}{100}=45\%

Event 3- To solve for the probability of this event, one needs to put the number of white marbles over the total number of marbles from Bage B, then convert the fraction to a percent,

\frac{white}{green+white}

Substitute,

\frac{8}{8+8}

\frac{8}{16}\\\\=\frac{1}{2}

Multiply this fraction by (50) to make the denominator (100) and convert it to a percent,

\frac{1}{2}*\frac{50}{50}\\\\=\frac{50}{100}=50\%

Event 4- Choosing a purple marble from Bag B

There are no purple marbles in Bag B, thus this is impossible, therefore the probability of this event is (0%)

Now order the percents from least to greatest,

0%, 45%, 50%, 100%

Substitute with the event numbers,

Event 4, Event 2, Event, 3, Event 1

5 0
3 years ago
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