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3 years ago

The roots of the equation 3x^2+2x+7=0

Mathematics

2 answers:

andrew-mc [135]3 years ago

8 0

There are no roots of this equation, they are all imaginary numbers.

romanna [79]3 years ago

3 0

Your question: The roots of the equation 3x^2+2x+7=0

Answer: I might have found the answer, which is linked in there.

Good luck, mate!

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PLEASE HELP EXPRESSIONS!!!! 15 points

Andru [333]

Answer:

C) $-14w+12$

Step-by-step explanation:

$10-7w-13-7w+15$

Group the similar terms together:

$-7w-7w+10-13+15$

Add/Subtract the w:

$-14w+10-13+15$

Add/Subtract the numbers:

$-14w+12$

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3 years ago

Read 2 more answers

If $5000 is invested at an interest rate of 3.396 compounded monthly for 10 years, what would be the balance in the account

saul85 [17]

Answer: D

Step-by-step explanation:

Months = 12 x 10 = 120months

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5000 X (1.03396)^120 = 275054.36

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4 years ago

When network cards are communicating, bits can occasionally be corrupted in transmission. Engineers have de- termined that the n

ycow [4]

Answer:

a) 11.40% probability of 5 bits being in error during the transmission of 1 kb

b) 11.60% probability of 8 bits being in error during the transmission of 2 kb

c) 0.01% probability of no error bits in 3kb

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the giveninterval.

Poisson distribution with mean of 3.2 bits/kb (per kilobyte).

This means that $\mu = 3.2kb$ , in which kb is the number of kilobytes.

(a) What is the probability of 5 bits being in error during the transmission of 1 kb?

This is P(X = 5) when $\mu = 3.2$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 5) = \frac{e^{-3.2}*3.2^{5}}{(5)!} = 0.1140$

11.40% probability of 5 bits being in error during the transmission of 1 kb

(b) What is the probability of 8 bits being in error during the transmission of 2 kb?

This is P(X = 8) when $\mu = 2*3.2 = 6.4$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 8) = \frac{e^{-6.4}*6.4^{8}}{(8)!} = 0.1160$

11.60% probability of 8 bits being in error during the transmission of 2 kb

(c) What is the probability of no error bits in 3kb?

This is P(X = 0) when $\mu = 3*3.2 = 9.6$

Then

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-9.6}*9.6^{0}}{(0)!} = 0.0001$

0.01% probability of no error bits in 3kb

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3 years ago

A student draws a triangle with a perimeter of 36cm. The student says the longest length is 18cm. How do you know the student is

Crazy boy [7]

The length of the first two sides of a triangle must be greater than the length of the last side. If the longest length were 18, the first two sides would be too short. 36-18=18, 18 is equal not greater than 18 which means the sum of the first two sides are too short.

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4 years ago

Jessie bought a t-shirt for $6. It was originally $8.What percent discount did she receive?

kvasek [131]

Jesse received a 25% discount.

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3 years ago

The roots of the equation 3x^2+2x+7=0​

The roots of the equation 3x^2+2x+7=0