Write the expression (4x-2).(6x 7) in the standard form of a anquadratic expression,ax^2 bx c what are the values of the coeffic
ient of each term and the constant term
1 answer:
Hello:
<span>(4x-2)(6x+ 7)=24x²+28x-12x-14
= 24x²+16x-14
</span><span>in the standard form : ax²+bx+c a = 24 b=16 c=-14</span>
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*I think you meant scientific notation.*
23 in scientific notation would be 2.3 x 10^1.
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Step-by-step explanation:
Im not so sure but, 3x2=6; 2x3=6; 6+6=12
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No please! Mr excuse me I am not your type bye
