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Andreas93 [3]
3 years ago
9

INSTRUCTIONS: A medincine for dogs indicates that the medicine should be administered in the ration 0.5 tsp per 5 lbs, based on

the weight of the dog.
Jaime has a 60 lb dog. She plans to give the dog 12 teaspoons of medicine. Is she administering the medicine correctly?

Please, if you can, put it in Step By Step instructions.
Mathematics
1 answer:
fomenos3 years ago
7 0
12 teaspoons of medicine times .5 equals 6.0 
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Please please help me............
Cloud [144]

Answer:

x = 12.

Step-by-step explanation:

2x + 6 + 4x + 2 = 2(5x - 20)     (The sum of the outer parallel sides = 2 * middle parallel line).

6x + 8 = 10x - 40

48 = 4x

x = 12.

5 0
4 years ago
|5z−8|=7
Step2247 [10]

Answer:

z = \frac{1}{5}, z = 3

Step-by-step explanation:

The absolute value function always returns a positive value.

However, the expression inside can be positive or negative, that is

5z - 8 = 7 ( add 8 to both sides )

5z = 15 ( divide both sides by 5 )

z = 3

OR

- (5z - 8) = 7

- 5z + 8 = 7 ( subtract 8 from both sides )

- 5z = - 1 ( divide both sides by - 5 )

z = \frac{1}{5}

As a check

Substitute these values into the left side of the equation and if equal to the right side then they are the solutions

z = 3

left side = | 15 - 8 | = | 7 | = 7 = right side

z = \frac{1}{5}

left side = | 1 - 8 | = | - 7 | = 7 = right side

Thus z = \frac{1}{5}, z = 3 are the solutions

5 0
3 years ago
Please help me with answer I need help now
Mama L [17]

Answer:

2 + 3

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
14. Shaun has a bag with 12 yellow tiles and
ollegr [7]
3 should be added to the tiles
5 0
4 years ago
The ratio of the corresponding side lengths of two similar posters is 7 in:20 in. What is the ratio of the perimeters?
gregori [183]
The ratio of their perimeters is still 7:20. The poster is a rectangle shape. If the length of each side of a poster is proportional to the other by a certain ratio, the sum of the lengths of all sides is also proportional by the same ratio. You can suppose the lengths of four sides of poster A are 7a, 7b, 7c, 7d, so poster B has 20a, 20b, 20c, 20d. (7a+7b+7c+7d)/(20a+20b+20c+20d)=7(a+b+c+d)/20(a+b+c+d)=7/20.
4 0
3 years ago
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