The average hight will be lower
3 11/30
steps to this: here you have to Rewrite our equation with parts separated
=1+15+2+16
Solving the whole number parts
1+2=3
Solving the fraction parts
15+16=?
Find the LCD of 1/5 and 1/6 and rewrite to solve with the equivalent fractions.
LCD = 30
630+530=1130
Combining the whole and fraction parts
3+1130=31130
Solution by Formulas
First:
Convert any mixed numbers to fractions.
Then your initial equation becomes:
65+136
Applying the fractions formula for addition,
=(6×6)+(13×5)5×6
=36+6530
=10130
Simplifying 101/30, the answer is
=31130
Complete Question
An F5 tornado is classified as having mean wind speeds greater than 261 mph. In an effort to classify a recent tornado, 20 wind speed measurements were randomly selected from within the path of the tornado. Suppose the mean wind speed for this tornado really is greater than 261 mph with a sample standard Deviation 41.09 mph. Based on the data, if we fined little to no evidence against the null hypothesis that the mean wind speed is 261 mph, we have made _______________.
Answer:
![P-value=0.3322](https://tex.z-dn.net/?f=P-value%3D0.3322)
Step-by-step explanation:
From the question we are told that:
Sample size ![n=20](https://tex.z-dn.net/?f=n%3D20)
Population mean
Sample mean
Sample standard deviation
Generally the equation t test statistics is mathematically given by
![t=\frac{\=x-\mu}{\frac{s}{\sqrt{n} } }](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B%5C%3Dx-%5Cmu%7D%7B%5Cfrac%7Bs%7D%7B%5Csqrt%7Bn%7D%20%7D%20%7D)
![t=\frac{265.1-261}{\frac{41.09}{\sqrt{20} } }](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B265.1-261%7D%7B%5Cfrac%7B41.09%7D%7B%5Csqrt%7B20%7D%20%7D%20%7D)
![t=0.446](https://tex.z-dn.net/?f=t%3D0.446)
Therefore
Pvalue from table is
![P-value=0.3322](https://tex.z-dn.net/?f=P-value%3D0.3322)