So let’s say the equation is x^2 (x squared) -4x + 8 = 0. So you have to eventually graph a palabara. So to get the vertex, you have to find the line of symmetry (this plays a big part). So the formula for the line of symmetry is x= -b/2a. So A is this equation is 1. B is -4. C is 8. So you would plug these numbers in and you get 2. So (2,0) is your like of symmetry. Now you have to plug 2 back in for x. So when you do that you get 4 so the vertex is (2,4). So the vertex is (2, 4) and basically what the vertex is is it is the highest or lowest point of a palabara. So you can tel if it opens up or down by looking is A is negative or positive. If A is negative the it opens down. If it is positive then it opens up. So now you just put points in. Create a t chart. Like x/y. So when X is 1 for example, y is 5. So you graph (1, 5) and you graph the point that is the same distance from the line of symmetry. You do this until you have 5 points. I hope this helps. It’s hard to teach this over text.
Answer:
Step-by-step explanation:
length of window=x ft
width of window=4 ft
area=4x
12<4x<24
divide by 4
3<x<6
Answer:
Slope of the line would be 
Hope this helps!
Answer:
.
Step-by-step explanation:
We are given
and
are zeros of the polynomial
.
We want to find the value of
if
.
Lets use veita's formula.
By that formula we have the following equations:
(-b/a where the quadratic is ax^2+bx+c)
(c/a)
Let's simplify those equations:

If
and
, then
.
Let's solve this for k:
Subtract 6 on both sides:

Find a common denominator:

Simplify:
.
1. L is parallel to n 1. Given
2. angle 2 ≅ angle 6 a. corresponding angles
3. angle 4 ≅ angle 2 b. vertical angles
<span>4. angle 6 ≅ angle 4 c. alternate interior angles
corresponding angles are angles found in matching corners.
vertical angles are angles that share the same vertex
alternate interior angles are angles found on the opposite sides of the transversal but inside the two parallel lines</span>