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3 years ago

First step when solving 2x+8=8

Mathematics

2 answers:

tresset_1 [31]3 years ago

8 0

Answer:

subtract 8 on both sides

Step-by-step explanation:

Pavlova-9 [17]3 years ago

5 0

Steps to solve:

2x + 8 = 8

~Subtract 8 to both sides

2x + 8 - 8 = 8 - 8

~Simplify

2x = 0

~Divide 2 to both sides

2x/2 = 0/2

~Simplify

x = 0

The first step is to subtract 8 to both sides.

Best of Luck!

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8 0

3 years ago

Solve the inequality <br> 5x+2 < 32

AnnyKZ [126]

Answer:

x<6

Step-by-step explanation:

First, let's work on the left hand side of your inequality, the 5x+2

This means, for instance, to see if it can be simplified at all.

Multiply x and 5

Multiply x and 1

The x just gets copied along.

The answer is x

5*x evaluates to 5x

5*x+2 evaluates to 5x+2

So, all-in-all, the left hand side of your inequality can be written as: 5x+2

Now, let's work on the right hand side of your inequality, the 32

The right hand side of your inequality can be written as: 32

So with these (any) simplifications, the inequality we'll set out to solve is:

5x+2 ‹ 32

Move the 2 to the right hand side by subtracting 2 from both sides, like this:

From the left hand side:

2 - 2 = 0

The answer is 5x

From the right hand side:

32 - 2 = 30

The answer is 30

Now, the inequality reads:

5x ‹ 30

To isolate the x, we have to divide both sides of the inequality by the other "stuff" (variables or coefficients)

around the x on the left side of the inequality.

The last step is to divide both sides of the inequality by 5 like this:

To divide x by 1

The x just gets copied along in the numerator.

The answer is x

5x ÷ 5 = x

30 ÷ 5 = 6

The solution to your inequality is:

x ‹ 6

8 0

2 years ago

Read 2 more answers

write a linear equation that intersects y=x^2 at two points. Then write a second linear equation that intersects y=x^2 at just o

Liula [17]

We know that $y = x^2$ is a parabola, concave up, with vertex in the origin $(0,0)$

So, we may use three horizontal lines for our purpose: any horizontal line above the x axis will intersect the parabola twice. The x axis itself intersects the parabola once on the vertex, while any horizontal line below the x axis won't intercept the parabola.

Here's the examples:

The horizontal line $y = 4$ intercepts the parabola twice: the system $y = x^2,\ y = 4$ is solved by $x^2=4 \implies x = \pm 2$
The horizontal line $y=0$ intercepts the parabola only once: the system is $y=x^2,\ y=0$ which yields $x^2=0\implies x=0$ which is a repeated solution
The horizontal line $y=-5$ intercepts the parabola only once: the system is $y=x^2,\ y=-5$ which yields $x^2=-5$ which is impossible, because a squared number can't be negative.