First step when solving 2x+8=8

Mathematics

2 answers:

tresset_1 [31]3 years ago

8 0

Answer:

subtract 8 on both sides

Step-by-step explanation:

Pavlova-9 [17]3 years ago

5 0

Steps to solve:

2x + 8 = 8

~Subtract 8 to both sides

2x + 8 - 8 = 8 - 8

~Simplify

2x = 0

~Divide 2 to both sides

2x/2 = 0/2

~Simplify

x = 0

The first step is to subtract 8 to both sides.

Best of Luck!

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I need the help for number 7 plz help me as soon as possible plz help me

Alisiya [41]

Answer:

Step-by-step explanation:

you need to divide both 15 and 25 by 5

15 divided by 5 = 3

25 divided by 5 = 5

8 0

2 years ago

Evaluate the integral ∫2−1|x−1|dx

defon

I think you might be referring to the definite integral,

$\displaystyle \int_{-1}^2|x-1|\,\mathrm dx$

Recall the definition of absolute value:

$|x| = \begin{cases}x&\text{if }x\ge0\\-x&\text{if }x$

Then $|x-1|=x-1$ if $x\ge1$ , and $|x-1|=1-x$ is $x$ . So spliting up the integral at <em>x</em> = 1, we have

$\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \int_{-1}^1(1-x)\,\mathrm dx + \int_1^2(x-1)\,\mathrm dx$

The rest is simple:

$\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \left(x-\dfrac{x^2}2\right)\bigg|_{-1}^1 + \left(\dfrac{x^2}2-x\right)\bigg|_1^2 \\\\ = \left(\left(1-\frac12\right)-\left(-1-\frac12\right)\right) + \left(\left(2-2\right)-\left(\frac12-1\right)\right) \\\\ = \boxed{\frac52}$