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2 years ago

Which expressions represent 1 more than the product of 5 and 2?

Mathematics

2 answers:

Gnesinka [82]2 years ago

7 0

4thhhhhhhhhhhhhhhhhh ans

Karolina [17]2 years ago

4 0

2 and 4 are the answers that apply to this statement

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The area of a rectangle is 37.5 square inches. The length of the rectangle is 15 inches. What is the width of the rectangle?

Svetlanka [38]

Here is how to find the answer for this problem.
We know that the formula for getting the area of the rectangle is A = Length x Width. Given that the area is 37.5 inches squared and the length is 15 inches, let us just plug in the values. Let w be width.
35.7 in^2 = 15 in x w
Next, we divide both sides by 15 and this is the result
w = 2.5 inches.
Therefore, the answer would be 2.5 inches.
Hope this answer helps. Thanks for posting your question.

7 0

2 years ago

a cube with side lengths s, has a volume of 216 cubic centimeters. the equation s^3 = 216 shows the volume of a cube. What is th

Umnica [9.8K]

You would take cubic root of both sides.

6³ = 216 so ∛216 = 6

So side length would be 6 <span>centimeters
</span>
Final answer: 6 cm

3 0

2 years ago

Classify the quadratic equation based on the number of solutions

BigorU [14]

QUESTION 1

The given equation is

$3 {x}^{2} + 2x = - 4$

We rewrite in the form,

$a {x}^{2} + bx + c = 0$

This implies that,

$3 {x}^{2} + 2x + 4 = 0$

$a=3,b=2,c=4$

We can use the determinant to find the number of solutions without necessarily solving the equation.

$D=b^2-4ac$

$D=2^2-4(3)(4)$

$D=4-48$

$D=-44$

Since the determinant is negative the equation

$3 {x}^{2} + 2x = - 4$

has no solution.

QUESTION 2

The given equation is

$5 {x}^{2} + 14 = 19$

$5 {x}^{2} + 14 - 19 = 0$

$5 {x}^{2} - 5= 0$

${x}^{2} - 1= 0$

$D=0^2-4(1)( - 1)$

$D=4$

Since the determinant is positive, the equation

$5 {x}^{2} + 14 = 19$

has two solutions.

QUESTION 3

The given equation is

$2 {x}^{2} + 5 = 2$

This implies that,

$2 {x}^{2} + 5 - 2 = 0$

$2 {x}^{2} + 3 = 0$

$a=2,b=0,c=3.$

The determinant is

$D= {0}^{2} - 4(2)(3)$

$D= - 24$

Since the determinant is negative, the equation

$2 {x}^{2} + 5 = 2$
has no solution.

QUESTION 4

The given equation is

$2 {x}^{2} + 3x = 5$

We rewrite to obtain,

$2 {x}^{2} + 3x - 5 = 0$

$a=2,b=3,c=-5$

The determinant is

$D= {3}^{2} - 4(2)( - 5)$

$D= 9 + 40$

$D= 49$

Since the determinant is positive the equation

$2 {x}^{2} + 3x = 5$

has two solutions.

QUESTION 5

The given equation is

$4 {x}^{2} + 12x = - 9$

We rewrite to obtain,

$4 {x}^{2} + 12x + 9 = 0$

$a=4,b=12,c=9$

We substitute in the determinant formula to obtain,

$D=12^2 - 4(4)(9)$

.
$D=144- 144$

$D=0$

Since the determinant is zero the equation

$4 {x}^{2} + 12x = - 9$
has only one root.

5 0

3 years ago

Read 2 more answers

621 Tons is 45% of what number of tons?

Yanka [14]

To find the answer, you just need to take:
621÷45%=1380
Check:
1380×45%=621 tons. As a result, 621 tons is 45% of 1380 tons. Hope it help!

3 0

3 years ago

Used addition properties and<br> strategies to find the sum 74+35+16+45=

iVinArrow [24]

74 + 35 + 16 + 45 =

= 74 + 16 + 35 + 45

= 70 + 4 + 10 + 6 + 30 + 5 + 40 + 5

= 70 + 10 + 4 + 6 + 30 + 40 + 5 + 5

= 80 + 10 + 70 + 10

= 80 + 10 + 10 + 70

= 100 + 70

= 170

4 0

2 years ago