Question

If an object is projected upward from ground level with an initial velocity of 96 ft per​ sec, then its height in feet after t seconds is given by ​s(t)equalsminus16tsquaredplus96t. Find the number of seconds it will take to reach its maximum height. What is this maximum​ height?

Answer 1

Answer:

Number of seconds to reach maximum height = 3 seconds

Maximum height = 144 ft

Step-by-step explanation:

We are given that;

s(t) = -16t² + 96t

Now, s(t) is a function whose graph is an upside-down parabola, so the maximum s value occurs at the vertex.

Thus, the applicable formula for coordinate of vertex is t = -b/(2a) where a is the coefficient -16 and b is 96

Thus,t = -96/(2 x - 16)

t = 96/32

t = 3

Thus maximum height will be at 3 seconds.

Thus;

Max height = s(3) = -16(3)² + 96(3)

Max height = -144 + 288 = 144 ft