Answer:
give my about ten mins i got to finish this final exam for math seg 1
Step-by-step explanation:
Given: 7r+3r-8=8+2r
Simplify: 10r-8=8+2r
Addition: add 8 to each side: 10r=16+2r
Subtraction: Take 2r from each side: 8r=16
Division: Divide each side by 8 for answer: r=2
Answer: r=2
Answer:
2/3 (0,-3) is one possible answer.
Step-by-step explanation:
y -1 = 2/3(x-6) We want to get this into the slope intercept form of a line. We want it to be in the form y = mx + b. Let's clear the fraction first by multiplying the whole equation through by 3.
3(y - 1) = 3[2/3(x - 6)]
3y -3 = 2(x -6)
3y - 3 = 2x -12
3y = 2x - 9 Now divide all the way through by 3 to get
y = 2/3x - 3
y = mx + b. The m part is the slope. In this equation the slope is 2/3
There are in infinite amount of points on a line. I do not know if they give you a picture or if you are just to create your own. I am going to create a point that have x = 0. I get to pick the point. I could pick any number. 0 is just usually really easy. So, if I substitute 0 for x I will get:
y = 2/3(0) - 3
y = 1 so my point is (0,-3)
Now that I think about it, I do not think that I would start out clearing the fraction even though it works. I think that I would do it like this"
y - 1 = 2/3(x - 6) Distribute the 2/3 through (x - 4) to get
y-1 = 2/3x -4 I can make -6 a fraction by putting it over 1. Now we have 2/3(-6/1) multiply across to get -12/3. A positive times a negative is a negative. -12 divided by 3 is -4.
y - 1 = 2/3x -4 now add 1 to both sides.
y = 2/3x -3
Step-by-step explanation:
so ,
Question 6 :-
5 × (3+4) - 4
first solve the Bracket ......
5 × (7) - 4
after multiplication ......
35 - 4
= 31
so , Answer is 1st one ....
Question 7 :-
8 + 1/2 × (6-2) -1
so , here also solve the Bracket first .....
8 + 1/2 × (4) - 1
after multiplication .....
8 + 2 - 1
after + and - .......
10 - 1
= 9 .......
so , Answer is 2nd one .....
Answer:
x = -2
Step-by-step explanation:
The tangent line has length "x + 8"
The secant line has length "x + 6 + 5", where
5 is the inner part
x + 6 is the outer part
Now,
the secant-tangent theorem tells us that square of the tangent line is equal to the outer segment of secant line multiplied by length of whole secant line.
So, we can say:

We can solve for x shown below:

The value of x is -2