Hello, you haven't provided the system of equations, therefore I will show you how to do it for a particular system and you can follow the same procedure for yours.
Answer:
For E1 -> Exactly one
For E2 -> None
For E3 -> Infinitely many
Step-by-step explanation:
Consider the system of equations E1: y = -6x + 8 and 3x + y = 4, replacing equation one in two 3x -6x +8 = 4, solving x = 4/3 and replacing x in equation one y = 0. This system of equations have just one solution -> (4/3, 0)
Consider the system of equations E2: y = -3x + 9 and y = -3x -7, replacing equation one in two -3x + 9 = -3x -7, solving 9 = -3. This system of equations have no solution because the result is a fallacy.
Consider the system of equations E3: 2 = -6x + 4y and -1 = -3x -2y, taking equation one and solving y = 1/2 + 3/2x, replacing equation one in two -1 = -3x -1 +3x, solving -1 = -1. This system of equations have infinitely many solution because we find a true equation when solving .
Answer:
x = 12
Step-by-step explanation:
1/24x2=1/12x2-1/x
1/12=1/6-1/x
1/x=1/6-1/12
1/x=1/12
x=12
I believe it could be weight today=193 goal weight=182
Answer:
$4440
Step-by-step explanation:
From the question, the annual cost of the plan is $14800
The employer pays 70% 0f the cost.
⇒70/100 ×14800 =$10360
Remaining amount to pay=
14800-10360=$4440
4w-12=6w-36+14
4w-12=6w-22
10=2w
5=w
(I think)
