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brilliants [131]
3 years ago
7

Can somebody please explain how to do this?

Mathematics
2 answers:
erastova [34]3 years ago
6 0
As we already have the value of y,we can put it into another equation.

Here's how we can solve the equation:

y = 2x+48...(1)
y = 8x...(2)

Put (2) into (1)

(8x) = 2x+48
8x-2x = 48
6x = 48
x = 8...(3)

Put (3) into (1)
y = 8(8)
y = 64

Thus, x=8, y+64

Hope it helps!
Inessa [10]3 years ago
3 0

x = -24 + y/2

y = 8x

I hope this helped :)

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Solve -8 = 2y – 2. Show your work and how to check your solution.
Mashcka [7]
Answer: y = -3

Explanation:

-8 = 2y - 2
-2y = -2 + 8
y = 6/-2
y = -3
4 0
2 years ago
Find x in the following diagram
andreyandreev [35.5K]

Answer:

x = 71

Step-by-step explanation:

The sum of the measures of the exterior angles of a polygon is always 360°.

A triangle has 3 exterior angles.

152+ 137+x = 360

Combine like terms

289 +x = 360

Subtract 289 from each side

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8 0
3 years ago
PLEASE HELP!!!! 20 POINTS!!!!
galben [10]
These are two questions and two answers.

Question 1) Which of the following polar equations is equivalent to the parametric equations below? 

<span> x=t²
y=2t</span>

Answer: option <span>A.) r = 4cot(theta)csc(theta)
</span>

Explanation:

1) Polar coordinates ⇒ x = r cosθ and y = r sinθ

2) replace x and y in the parametric equations:

r cosθ = t²
r sinθ = 2t

3) work r sinθ = 2t

r sinθ/2 = t 
(r sinθ / 2)² = t²

4) equal both expressions for t²

r cos θ = (r sin θ / 2 )²

5) simplify

r cos θ = r² (sin θ)² / 4

4 = r (sinθ)² / cos θ

r = 4 cosθ / (sinθ)²

r = 4 cot θ csc θ ↔ which is the option A.


Question 2) Which polar equation is equivalent to the parametric equations below?

<span> x=sin(theta)cos(theta)+cos(theta)
y=sin^2(theta)+sin(theta)</span>

Answer: option B) r = sinθ + 1


Explanation:

1) Polar coordinates ⇒ x = r cosθ, and y = r sinθ

2) replace x and y in the parametric equations:

a) r cosθ = sin(θ)cos(θ)+cos(θ)
<span> b) r sinθ =sin²(θ)+sin(θ)</span>

3) work both equations

a) r cosθ = sin(θ)cos(θ)+cos(θ) ⇒ r cosθ = cosθ [ sin θ + 1]  ⇒ r = sinθ + 1


<span> b) r sinθ =sin²(θ)+sin(θ) ⇒ r sinθ = sinθ [sinθ + 1] ⇒ r = sinθ + 1
</span><span>
</span><span>
</span>Therefore, the answer is r = sinθ + 1 which is the option B.
6 0
3 years ago
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The length of a rectangle is 3 more than five times its width. If the perimeter of
AleksandrR [38]

Answer:

Image result for The length of a rectangle is 3 more than five times its width. If the perimeter of the rectangle is 30 meters, find the dimensions of the rectangle.

To find the width, multiply the length that you have been given by 2, and subtract the result from the perimeter. You now have the total length for the remaining 2 sides. This number divided by 2 is the width.

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A. 4x^2 +5x-4y-3
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