Answer:
1 or -0.5±1.9365i
Step-by-step explanation:
We know that 
So plug in x=a and y=1/a, (a-1/a)^3+3*a*1/a*(a-1/a)=4
Let a-1/a=k, k^3+3k=4, k=1 or a complex conjugate -0.5±1.9365i
That's the answer.
Given:
1st map = 8 cm
2nd map = 6 cm
1 cm in the map is equal to 2 km on the actual trail.
8 cm * 2km/1cm = 16 km is the actual length of the trail in the first map
6 cm * 2km/1cm = 12 km is the actual length of the trail in the second map.
I'm not sure on how to get the scale factor from the map to the actual trail. I'm confused if I had to consider cm and km because 1km is equal to 100,000 cm.
Proportion of the second map to the first map is 6/8
6/8 = x/3 → 6*3 = 8x → 18/8 = x → 2.25
6/8 = x/4 → 6*4 = 8x → 24/8 = x → 3
6/8 = x/5 → 6*5 = 8x → 30/8 = x →3.75
The side measure of the triangle in the second map is only 75% of the side measure of the triangle in the first map.
Answer: 64
Step-by-step explanation:
2^3 = 8
2^-3=1/8
8/1/8=64
