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Viktor [21]
3 years ago
7

Simplify 1+sinx/cosx+cosx/1+sinx

Mathematics
1 answer:
Dmitry [639]3 years ago
6 0
\frac{1 + sin(x)}{cos(x)} + \frac{cos(x)}{1 + sin(x)}
\frac{[1 + sin(x)][1 +sin(x)]}{cos(x)[1 + sin(x)]} + \frac{cos(x)[cos(x)]}{cos(x)[1 + sin(x)]}
\frac{1 + 2sin(x) + sin^{2}(x)}{cos(x)[1 + sin(x)]} + \frac{cos^{2}(x)}{cos(x)[1 + sin(x)]}
\frac{1 + 2sin(x) + sin^{2}(x) + cos^{2}(x)}{cos(x)[1 + sin(x)]}
\frac{1 + 2sin(x) + 1}{cos(x)[1 + sin(x)]}
\frac{1 + 1 + 2sin(x)}{cos(x)[1 + sin(x)]}
\frac{2 + 2sin(x)}{cos(x)[1 + sin(x)]}
\frac{2[1 + sin(x)]}{cos(x)[1 + sin(x)]}
\frac{2}{cos(x)}
2sec(x)
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IgorC [24]

Answer:

Interest rate, R = 244%

Step-by-step explanation:

Given the following data;

Principal = $270

Simple interest = future amount - principal = 309.60 - 270 = $39.60

Time = 22/360 = 0.06 years

To find the interest rate?

Mathematically, simple interest is calculated using this formula;

S.I = \frac {PRT}{100}

Where;

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Substituting into the equation, we have;

39.60 = \frac {270*R*0.06}{100}

Cross-multiplying, we have;

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Answer:

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