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3 years ago

Please help!!!!!!!!!!

Mathematics

2 answers:

EastWind [94]3 years ago

3 0

C 12 am ma js n a wiw. Jdjdjek koala.

stealth61 [152]3 years ago

3 0

Answer:

Step-by-step explanation:

The length is 6 meters more than twice the width of the rectangle, so...

If the width is 10 meters, that means the length must be 26 meters.

10 x 2 + 6 = 26

The perimeter equals 72 meters, so let's see if the sum of the sides add up.

w = 10 l = 26

10 + 10 = 20

26 + 26 = 52

20 + 52 = 72!

Since the sum of the sides equals 72, the width of the rectangle must be 10, and the length must be 26.

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11Alexandr11 [23.1K]

Answer:

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Step-by-step explanation:

6 0

3 years ago

Find the measures of the supplementary angles that satisfy each case.

seropon [69]

Answer:

67.5°, 107.5°

Step-by-step explanation:

For supplementary angles, their sum equals 180°.

Let x be the first angle and y be the second angle, then

x + y = 180°.

It is given that x = y + 45°.

So x + y = 180°

substituting x into the equation, we have

y + 45° + y = 180°

simplifying, we have

2y + 45° = 180°

collecting like terms, we have

2y = 180° - 45°

2y = 135°

dividing through by 2, we have

y = 135°/2

y = 67.5°

Since y = 67.5°

then x = y + 45°

x = 67.5° + 45°

x = 107.5°

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3 years ago

Helppppp 3. Elaina's old bicycle had tires with a 12-inch diameter. Her new bicycle has tires with a 16-inch diameter. What is t

Setler [38]

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2 years ago

Read 2 more answers

Someone please help me!!!!!

Katarina [22]

1. Answer (D). By the law of sines, we have $\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}$ in any $\triangle ABC.$

2. Answer (C). The law of cosines, $c^2=a^2+b^2-2ab\cos C,$ accepts up to three sides and an angle as an input.

3. Answer (D). Although this triangle is right, we are not given enough information to uniquely determine its sides and angles - here, we need either one more side or one more angle.

4. Answer (D). Don't get tripped up by answer choice (C) - this is just a rearrangement of the statement of the law of cosines. In choice (D), the signs of $a^2$ and $2ab\cos C$ are reversed.

5. Answer (B). By the law of sines, we have $\frac{5}{\sin 40^\circ}=\frac{3}{\sin\theta}.$ Solving gives $\theta\approx \boxed{23^\circ},157^\circ.$ Note that this is the <em>ambiguous (SSA) case</em> of the law of sines, where the given measures could specify one triangle, two triangles, or none at all!

6. Answer (A). Since we know all three sides and none of the angles, starting with the law of sines will not help, so we begin with the law of cosines to find one angle; from there, we can use the law of sines to find the remaining angles.

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3 years ago

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