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3 years ago

Which property is used in this following expression 9(3+2)=27+18

Mathematics

1 answer:

swat323 years ago

8 0

Answer:

associative property

Step-by-step explanation:i hope u enjoy!!!!!!!...

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The ratio of boys to girls in a classroom is 15 to 12 . What is the ratio of boys to total students in the classroom?

zheka24 [161]

Answer:

15 to 27 (which is equal to 5:9)

Step-by-step explanation:

The ratio 15 to 12 indicates that there is a total of 27 people in the classroom (15+12). So, if you want boys to total students, it's 15 to 27.

You can divide each of these by 3 to simplify it and get 5:9.

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3 years ago

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If JL and MO are parallel lines and mLKN = 49°, what is mMNK?

frez [133]

Answer:

65 Degrees

Step-by-step explanation:

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3 years ago

Solve using pemdas 3 plus 7 times 6 divided by 3

kondor19780726 [428]

Answer:

Step-by-step explanation:

3 + 7 * 6 / 3

PEMDAS says we multiply and add before adding and subtracting so we multiply first (going from left to right)

3 + 42 / 3

Then we divide

3 + 14 = 17

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3 years ago

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tatuchka [14]

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Step-by-step explanation:

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3 years ago

The face of the triangular concrete panel shown has an area of 22 square meters, and its base is 3 meters longer than twice its

Elodia [21]

Answer:

The length of the base is 11 meters.

Step-by-step explanation:

The diagram of the triangle is not shown; However, the given details are enough to solve this question.

Given

Shape: Triangle

Represent the height with h and the base with b

$b = 3 + 2h$

$Area = 22$

Required

Find the length of the base

The area of a triangle is calculated as thus;

$Area = \frac{1}{2} * b * h$

Substitute 22 for Area and 3 + 2h for b

The formula becomes

$22 = \frac{1}{2} * (3 + 2h) * h$

Multiply both sides by 2

$2 * 22 = 2 * \frac{1}{2} * (3 + 2h) * h$

$44 = (3 + 2h) * h$

Open the bracket

$44 = 3 * h + 2h * h$

$44 = 3h + 2h^2$

Subtract 44 from both sides

$44 - 44 = 3h + 2h^2 - 44$

$0 = 3h + 2h^2 - 44$

Rearrange

$0 = 2h^2 +3h - 44$

$2h^2 +3h - 44 = 0$

At this point, we have a quadratic equation; which is solved as follows:

$2h^2 +3h - 44 = 0$

$2h^2 + 11h - 8h - 44 = 0$

$h(2h + 11) - 4(2h + 11) = 0$

$(h - 4)(2h + 11) = 0$

Split the above

$(h - 4) = 0\ or\ (2h + 11) = 0$

$h - 4 = 0\ or\ 2h + 11 = 0$

Solve the above linear equations separately

$h - 4 = 0$

Add 4 to both sides

$h - 4 + 4 = 0 + 4$

$h = 0 + 4$

$h = 4$ ---- First value of h

$2h + 11 = 0$

Subtract 11 from both sides

$2h + 11 - 11 = 0 - 11$

$2h = 0 - 11$

$2h = -11$

Divide both sides by 2

$\frac{2h}{2} = -\frac{11}{2}$

$h = -\frac{11}{2}$ ------ Second value of h

Since height can be negative, we'll discard $h = -\frac{11}{2}$

Hence, the usable value of height is $h = 4$

Recall that $b = 3 + 2h$

Substitute 4 for h

$b = 3 + 2(4)$

$b = 3 + 8$

$b = 11$

Hence, the length of the base is 11 meters

3 0

4 years ago