All categories

3 years ago

Simplify fully square root 12 Square root 27 square root 50

Mathematics

2 answers:

meriva3 years ago

8 0

Answer:

$2 \sqrt{3}$

$3 \sqrt{3}$

$5 \sqrt{2}$

gizmo_the_mogwai [7]3 years ago

7 0

Hey here’s your answer

Square root of 12:- 12,144 3.464
Square root of 27:-5.196
Square root of 50:-50 as 2 times 25.

You might be interested in

The square root of 1521 = 39, evequate 390 to the 2nd power

ki77a [65]

Answer:

390 to the second power is 152100

4 0

3 years ago

A quadratic function is defined by

ella [17]

Answer:

1. The vertex of the graph of the function is (-4, 7)

2. The vertex represents a minimum value

3. The equation represented by the new graph is g(x) = (x + 4)² + 1

Step-by-step explanation:

The given quadratic function is given in vertex form, y = a·(x - h)² + k, as follows;

g(x) = (x + 4)² + 7

1. By comparing the given quadratic function and the vertex form of a quadratic equation, we have;

a = 1, h = -4, and k = 7

The vertex of the graph of the function, (h, k) = (-4, 7)

2. Given that a = 1 > 0, the graph of the quadratic function opens upwards and the vertex represents a minimum value

3. Shifting the graph 6 units down from where it is now will give;

The vertex = (h, k - 6) = (-4, 7 - 6) = (-4, 1)

h = -b/(2·a), k = (-b²/(4·a) + c = -a·h² + c

c = k + a·h²

Therefore, initial value of the constant term, c = -1×(-4)² + 7 = 23

After the shifting the graph 6 units down, c = 23 - 6 = 17

∴ k = 1 = -a·(-4)² + 17

∴ -16/16 = -1 = -a

a = 1

Therefore, the equation represented by the new graph is g(x) = (x + 4)² + 1.

5 0

3 years ago

A model airplane flew a distance of 330 feet in 15 seconds.

kondaur [170]

So whats the question

6 0

3 years ago

4. Solve 5x - 7x + 6 = -2(x - 3) * (5 Points) (5 Points) 2 infinitely many solutions

mezya [45]

-2x + 6 = -2x + 6

this problem has infinite solutions :)

7 0

3 years ago

Find the coordinates for the midpoint of the segment with endpoints give (3,5) and (-2,0)

Leto [7]

Answer:

The coordinates of the mid-point are :

$(\frac{1}{2}, \frac{5}{2})$

Step-by-step explanation:

We know that, the coordinates of the mid-point (x, y) of a line segment joining the points (x₁, y₁) and (x₂, y₂) is given by

$(x, y) = (\frac{x_{1} +x_{2} }{2},\frac{y_{1}+y_{2} }{2} )$

Now, we have the given points as (3, 5) and (-2, 0).

By using the above formula, coordinates of the mid-point (x, y) of the line-segment joining the points (3, 5) and (-2, 0) is given by,

$x = \frac{3+(-2)}{2} = \frac{3-2}{2} = \frac{1}{2}$

$y = \frac{5+0}{2} = \frac{5}{2}$

∴ coordinates of the mid-point of the line-segment joining the points (3,5) and (-2,0) is $(\frac{1}{2}, \frac{5}{2})$ .

8 0

3 years ago