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3 years ago

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Part a: if (6^2)^x = 1, the value of x is 0. the reason for it being 0 is because anything to the power of 0 equals 1. part b: i

f (6^0)^x = 1, then the value of x here is also ________

1 answer:

exis [7]3 years ago

4 0

The value of x is all real numbers because 6^0 is 1 and 1 raised to the power of any number will still be 1.

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