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d1i1m1o1n [39]
3 years ago
11

In a gear system, when you gain torque you lose what?

Computers and Technology
1 answer:
Katen [24]3 years ago
3 0
Space distance..............
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Why did NFL equip its players with RDIF tags?
SVEN [57.7K]

NFL equip its players with RDIF tags so as aid or support them to take a lot of statistical information about the players e.g. their position, speed, acceleration and others. The data taken is often used in making a lot of analysis and coaching decisions linked to the players.

<h3>Why did NFL equip it's players with RFID tags?</h3>

This is known to be often done so that it can aid location tracking, a lot of NFL equips each player with a minimum of two RFID tags.

Hence,  NFL equip its players with RDIF tags so as aid or support them to take a lot of statistical information about the players e.g. their position, speed, acceleration and others. The data taken is often used in making a lot of analysis and coaching decisions linked to the players.

Learn more about NFL from

brainly.com/question/15262528

#SPJ1

5 0
2 years ago
Return a version of the given string, where for every star (*) in the string the star and the chars immediately to its left and
lana [24]

Answer:

Explanation:

The following code is written in Java and uses a for loop with a series of IF ELSE statements to check the next and previous characters in a string. Checking to make sure that there are no asterix. If so it adds that character to the String variable output. Which is returned to the user at the end of the method. Two test cases have been created and the output can be seen in the attached image below.

class Brainly {

   public static void main(String[] args) {

       System.out.println(starOut("sm*eilly"));

       System.out.println(starOut("ab**cd"));

   }

   public static String starOut(String str) {

       String output = "";

       for (int i = 0; i < str.length(); i++) {

           if ((i != 0) && (i != str.length()-1)) {

               if ((str.charAt(i-1) != '*') && (str.charAt(i+1) != '*') && (str.charAt(i) != '*')) {

                   output += str.charAt(i);

               }

           } else {

               if ((i == 0) && (str.charAt(i) != '*') && (str.charAt(i+1) != '*')) {

                   output += str.charAt(i);

               } else if ((i == str.length()-1) && (str.charAt(i) != '*') && (str.charAt(i-1) != '*')) {

                   output += str.charAt(i);

               }

           }

       }

       return output;

   }

}

4 0
3 years ago
What is the dark, sticky substance that forms when tobacco is burned?
sashaice [31]

Answer: Tar.

Explanation:

A chemical substance made when tobacco is burned. Tar contains most of the cancer-causing and other harmful chemicals found in tobacco smoke. When tobacco smoke is inhaled, the tar can form a sticky layer on the inside of the lungs.

7 0
3 years ago
Write a program that generates a random number between 5 and 15 and asks the user to guess what the number is. If the user’s gue
stepan [7]

Answer: The c++ program for the number guessing game is given below.

#include <iostream>

using namespace std;

// method declaration without parameters

void game();

int main() {    

char reply;

// calling the game method

game();  

cout<<"Would you like to continue with the game ? Enter y to continue. Enter q to quit the game. " <<endl;

cin>>reply;  

if(reply == 'y')

    game();      

if(reply == 'q')

    cout<<"Quitting the game..."<<endl;  

return 0;

}

void game()

{

   int num, guess, attempt=0;  

num = (rand() % 10) + 6;  

cout<<endl<<"Welcome to the game of guessing the correct number "<<endl;  

   do

{    

    cout<<"Enter any number between 5 and 15. "<< endl;

    cin>>guess;      

    if(guess<5 || guess>15)

    {

        do

        {

            cout<<"Invalid number. Enter any number between 5 and 15. "<<endl;

            cin>>guess;

        }while(guess<5 || guess>15);

    }  

    if(guess < num)

    {

        cout<<"Too Low"<<endl;

        attempt++;        

    }

    if(guess > num)

    {

        cout<<"Too High"<<endl;

        attempt++;          

    }      

}while(guess != num);  

cout<<"Congratulations. You figured out my number in "<<attempt<< " attempts."<<endl;

}

Explanation:

The expression

(rand() % 10)

generates a random number between 0 and 9. 6 is added to generate a random number between 5 and 15.

The integer variable attempt is initialized to 0.

Next, user is asked to guess the number. If the user enters an invalid input, the do-while loop begins until a valid input is received from the user.

    cout<<"Enter any number between 5 and 15. "<< endl;

    cin>>guess;      

    if(guess<5 || guess>15)

    {

        do

        {

            cout<<"Invalid number. Enter any number between 5 and 15. "<<endl;

            cin>>guess;

        }while(guess<5 || guess>15);

    }  

User is prompted to input the guess using the same do-while loop as above. Until the user guesses the correct number, the loop continues. Each incorrect guess by the user, increments the variable attempt by 1. This represents the number of attempts done by the user to guess the correct number.

    if(guess < num)

    {

        cout<<"Too Low"<<endl;

        attempt++;        

    }

    if(guess > num)

    {

        cout<<"Too High"<<endl;

        attempt++;          

    }  

The random number generation and the guessing logic is put in a separate method game().

The entry and exit from the game only is put inside the main method.

4 0
4 years ago
Consider two different implementations, M1 and M2, of the same instruction set. There are three classes of instructions (A, B, a
Margaret [11]

Explanation:

A.)

we have two machines M1 and M2

cpi stands for clocks per instruction.

to get cpi for machine 1:

= we multiply frequencies with their corresponding M1 cycles and add everything up

50/100 x 1 = 0.5

20/100 x 2 = 0.4

30/100 x 3 = 0.9

CPI for M1 = 0.5 + 0.4 + 0.9 = 1.8

We find CPI for machine 2

we use the same formula we used for 1 above

50/100 x 2 = 1

20/100 x 3 = 0.6

30/100 x 4 = 1.2

CPI for m2 =  1 + 0.6 + 1.2 = 2.8

B.)

CPU execution time for m1 and m2

this is calculated by using the formula;

I * CPI/clock cycle time

execution time for A:

= I * 1.8/60X10⁶

= I x 30 nsec

execution time b:

I x 2.8/80x10⁶

= I x 35 nsec

6 0
3 years ago
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