1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
hodyreva [135]
3 years ago
8

what is the answer for this question a beaker contains 0.5 liters of solution Jordan uses 0.08 of solution for an experiment .ho

w much of the solution does Jordan use
Mathematics
1 answer:
DochEvi [55]3 years ago
8 0
You would add them together to find the total solution. 0.05 + 0.08= 0.58 
You might be interested in
the radius of the aluminum atom is 143pm. the radius of the aluminum atom is 54pm. by what percentage did the radius change as t
Dennis_Churaev [7]

Answer:

There was 62.23% change in radius as the ion formed.

Step-by-step explanation:

Given

Radius of Aluminium (Al) atom  = 143 pm

Radius of Aluminium (Al^{3+}) atom  = 54 pm

Change is the radius =  Radius of Aluminium (Al) atom - Radius of Aluminium (Al^{3+}) atom = 143 -54 = 89

Now to find % Change is the radius we will divide Change is the radius by Radius of Aluminium (Al) atom and multiply by 100 we get

% Change is the radius = \frac{\textrm{Change is the radius}}{\textrm{Radius of Aluminium (Al) atom}} \times 100 = \frac{89}{143}\times100= 62.23\%

Hence there was 62.23% change in radius as the ion formed.

4 0
4 years ago
To test Upper H 0 : sigma equals 1.6 versus Upper H 1 : sigma less than 1.6​, a random sample of size n equals 21 is obtained fr
kicyunya [14]

Answer:

Answer: is answer hope this helps

Step-by-step explanation:

8 0
3 years ago
ABC is an isosceles triangle with AB=BC ACD is a straight line work out the size of BCD
rusak2 [61]

Answer:

Triangle ABC is isosceles, with AC = BC. Angle ACD= 620 BCD is a straight line. 180-118=62 62:2-31 x= 31.

Step-by-step explanation:

plz mark as brainiest

hope it helps

5 0
3 years ago
A football player ran the ball for 40 yards, 45 yards, 48 yards, 52 yards, and 105 yards. What is the outlier?
Vinil7 [7]
An outlier is a value that is much higher or much lower than the rest of the values in the data set.

The answer here is 105 because it is nearly double all other values.
65 is incorrect because it's not even a value in the data set.
6 0
4 years ago
There are 4 white and 8 red roses in a bouquet. Find the ratios. The ratio of the number of red roses to the number of white ros
pychu [463]

Given:

Number of white roses = 4

Number of red roses = 8

To find:

The ratio of the number of red roses to the number of white roses.

Solution:

Using the given information, the ratio of the number of red roses to the number of white roses is

\text{Required ratio}=\dfrac{\text{Number of red roses}}{\text{Number of white roses}}

\text{Required ratio}=\dfrac{8}{4}

\text{Required ratio}=\dfrac{2}{1}

\text{Required ratio}=2:1

Therefore, the required ratio is 2:1.

7 0
4 years ago
Other questions:
  • Which point is a solution to the inequality shown in this graph?<br> A,B,C or D
    5·2 answers
  • What is y after the following statement is executed? x = 0; y = (x &gt; 0) ? 10 : -10;?
    9·1 answer
  • Can someone please help me with number 6? If so, you get 11 points!
    9·1 answer
  • 1. Simplify (4xy^2)^3(xy)^5 . 2. Simplify (2t^–3)^3(0.4r)^2
    9·1 answer
  • What is a possible step when solving for x? Select all that apply.
    12·1 answer
  • How to do this Question a please help from the smallest to the biggest
    6·2 answers
  • One teacher wants to give each student 3 1/4 slices of pizza. If the teacher has 13 slices of pizza, then how many students will
    9·1 answer
  • Lines l and m are parallel m
    8·1 answer
  • DB is a perpendicular bisector of ADC.<br> AC = 2x + 20 BC = 4x-2 Solve for x.<br> Find BC and AC.
    10·1 answer
  • Carlos bought 4 yards of packing tape. He used 1 3/5 yards on a package for his father and 2 1/3 for a package. How many yards o
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!