1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ira Lisetskai [31]
3 years ago
10

A science teacher collects 20 pints of lake water for a lab she is teaching.The lab requires each student to use 4 fluid ounces

of lake water.If 44 students are practicipating, how many pints of lake water will the teacher have left over?
Mathematics
1 answer:
spin [16.1K]3 years ago
3 0

Answer:

9 pints

Step-by-step explanation:

This is a unit question. Okay, we would be needing some conversions here. The most important to know first is how many ounces are in a pint.

It had been established that 1 pint contains 16 fluid ounces. This conversion will aid out calculations.

She collects 20 pints. This means she collected 20 * 16 ounces = 320 ounces

Each student is to use 4 fluid ounces and we have 44 students. The total number of ounces required by the students is simply 4 * 44 = 176 ounces

The amount in ounces left over would be 320 - 176 = 144 ounces

We are asked to get the number of pints left. Hence we need to know the number of pints equivalent to 144 ounces. This is equivalent to 144/16 = 9 pints

You might be interested in
what is the area, measured in square centimeters, of the triangle below? Do not include units in your answer
faltersainse [42]
3 x 4 = 12 or 4 x 3 = 12
7 0
2 years ago
Read 2 more answers
Keith works 8 hours per week. melba works 2250 minutes each week. who spends more time at work?
lord [1]

Answer:

Melba works more

Step-by-step explanation:

We need to compare with the same units

Lets convert hours to minutes

1 hour = 60 minutes

8 hours* 60 minutes/1hour = 480 minutes

Keith works 480 minutes

Melba works 2250 minutes

Melba works more

7 0
3 years ago
Read 2 more answers
Z^4-5(1+2i)z^2+24-10i=0
mixer [17]

Using the quadratic formula, we solve for z^2.

z^4 - 5(1+2i) z^2 + 24 - 10i = 0 \implies z^2 = \dfrac{5+10i \pm \sqrt{-171+140i}}2

Taking square roots on both sides, we end up with

z = \pm \sqrt{\dfrac{5+10i \pm \sqrt{-171+140i}}2}

Compute the square roots of -171 + 140i.

|-171+140i| = \sqrt{(-171)^2 + 140^2} = 221

\arg(-171+140i) = \pi - \tan^{-1}\left(\dfrac{140}{171}\right)

By de Moivre's theorem,

\sqrt{-171 + 140i} = \sqrt{221} \exp\left(i \left(\dfrac\pi2 - \dfrac12 \tan^{-1}\left(\dfrac{140}{171}\right)\right)\right) \\\\ ~~~~~~~~~~~~~~~~~~~~= \sqrt{221} i \left(\dfrac{14}{\sqrt{221}} + \dfrac5{\sqrt{221}}i\right) \\\\ ~~~~~~~~~~~~~~~~~~~~= 5+14i

and the other root is its negative, -5 - 14i. We use the fact that (140, 171, 221) is a Pythagorean triple to quickly find

t = \tan^{-1}\left(\dfrac{140}{171}\right) \implies \cos(t) = \dfrac{171}{221}

as well as the fact that

0

\sin\left(\dfrac t2\right) = \sqrt{\dfrac{1-\cos(t)}2} = \dfrac5{\sqrt{221}}

(whose signs are positive because of the domain of \frac t2).

This leaves us with

z = \pm \sqrt{\dfrac{5+10i \pm (5 + 14i)}2} \implies z = \pm \sqrt{5 + 12i} \text{ or } z = \pm \sqrt{-2i}

Compute the square roots of 5 + 12i.

|5 + 12i| = \sqrt{5^2 + 12^2} = 13

\arg(5+12i) = \tan^{-1}\left(\dfrac{12}5\right)

By de Moivre,

\sqrt{5 + 12i} = \sqrt{13} \exp\left(i \dfrac12 \tan^{-1}\left(\dfrac{12}5\right)\right) \\\\ ~~~~~~~~~~~~~= \sqrt{13} \left(\dfrac3{\sqrt{13}} + \dfrac2{\sqrt{13}}i\right) \\\\ ~~~~~~~~~~~~~= 3+2i

and its negative, -3 - 2i. We use similar reasoning as before:

t = \tan^{-1}\left(\dfrac{12}5\right) \implies \cos(t) = \dfrac5{13}

1 < \tan(t) < \infty \implies \dfrac\pi4 < t < \dfrac\pi2 \implies \dfrac\pi8 < \dfrac t2 < \dfrac\pi4

\cos\left(\dfrac t2\right) = \dfrac3{\sqrt{13}}

\sin\left(\dfrac t2\right) = \dfrac2{\sqrt{13}}

Lastly, compute the roots of -2i.

|-2i| = 2

\arg(-2i) = -\dfrac\pi2

\implies \sqrt{-2i} = \sqrt2 \, \exp\left(-i\dfrac\pi4\right) = \sqrt2 \left(\dfrac1{\sqrt2} - \dfrac1{\sqrt2}i\right) = 1 - i

as well as -1 + i.

So our simplified solutions to the quartic are

\boxed{z = 3+2i} \text{ or } \boxed{z = -3-2i} \text{ or } \boxed{z = 1-i} \text{ or } \boxed{z = -1+i}

3 0
1 year ago
Find the surface area of the right square pyramid. Round your answer to the nearest hundredth.
vlada-n [284]
A= a^2+2a\square root{\frac{a^2}{4}}+h^2
a=base=8
h=height=7
A=surface area
A=177
5 0
3 years ago
Read 2 more answers
Does someone mind helping me with this question? Thank you!
Kaylis [27]

Step-by-step explanation:

The sum of three angle of any triangle is <u>1</u><u>8</u><u>0</u><u>°</u>....

8 0
2 years ago
Read 2 more answers
Other questions:
  • Luigi had made a very large pizza pie for his neighborhood. He cut it into 256 pieces. How many slices of the pizza would Luigi
    7·1 answer
  • Do you guys know what’s the answer
    6·1 answer
  • How many different "like terms" are in this group? 3,4,5,z,x,-4
    6·1 answer
  • What is the solution set for 5x-3&lt;23 or 2x+7&gt;1?
    9·1 answer
  • 2a/b given a=-3/4 and b=1/2
    9·1 answer
  • Two angles in a triangle add up to 125 degrees what is the size if the third angle
    13·1 answer
  • I need hello ASAP!!!
    15·2 answers
  • The perimeter of a semicircle is 60 cm<br>Calculate its area ​
    15·2 answers
  • What type of transformation is shown?
    12·2 answers
  • I need help with a math question but apparently everyone is dead today..
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!