All categories

3 years ago

Each day, I use 4 bags of milk for tea. In how much of a day wlll I use 1/2 of a bag of milk?

1 answer:

3 0

1 day use 4 bags
? day use 1/2 bag

Cross multiply
(1•1/2)/4= 1/2•1/4= 1/8 of the day

In 1/8 of the day 1/2 of bag of milk will be used.

You might be interested in

Solve 32>2h+6h. Graph the solution.

aniked [119]

God loves all of you, remember that oK <3 32>2h+6h is

5 0

3 years ago

(2 * 10^-2) +(9*10^-3)<br> Please before Wednesday

anzhelika [568]

Answer:

try symnolab it helps a lot with math but the answer is 29/1000 0r 0.029

Step-by-step explanation: Hopes this helps :)

3 0

3 years ago

Read 2 more answers

An isosceles triangle has 2 equivalent sides. The perimeter of an isosceles triangle is 84 centimeters. The measure of one of th

Pani-rosa [81]

Well, to find your solution to this problem, I would subtract 84 from 32 = 52. I would divide the number by 2, which equals 26. So, side lengths are 32, 26, and 26.

Or, another one is that 2 sides have the length of 32, so 32+32=64. I would subtract 84 from 64 and get 20. So, side lengths are 32, 32, and 20.

3 0

3 years ago

The center of a hyperbola is (−4,3) , and one vertex is (−4,7) . The slope of one of the asymptotes is 2.

Monica [59]

Answer:

The answer to your question is below

Step-by-step explanation:

C (-4, 3)

V (-4, 7)

asymptotes = 2 = $\frac{b}{a}$

- This is a vertical hyperbola, the equation is

$\frac{(y - k)^{2} }{a^{2} } + \frac{(x - h)^{2} }{b^{2} } = 1$

slope = 2

a is the distance from the center to the vertex = 4

b = 2(4) = 8

$\frac{(y - 3)^{2} }{4^{2} } + \frac{(x + 4)^{2} }{8^{2} } = 1$

$\frac{(y - 3)^{2} }{16} + \frac{(x + 4)^{2} }{64} = 1$

7 0

3 years ago

Read 2 more answers

If DGH ~ DEF, Find the value of X

DIA [1.3K]

Answer:

$x=25$

Step-by-step explanation:

we know that

DGH ~ DEF ---> given problem

Remember that

If two triangles are similar, then the rtio of its corresponding sides is proportional and its corresponding angles are congruent

$\frac{DG}{DE}=\frac{GH}{EF}$

substitute the given values

$\frac{52}{91}=\frac{x+3}{2x-1}$

$(2x-1)52=(x+3)91\\104x-52=91x+273\\104x-91x=273+52\\13x=325\\x=25$

4 0

3 years ago