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Lorico [155]
3 years ago
15

Given the char * variables name1, name2, and name3, write a fragment of code that assigns the largest value to the variable max

(assume all three have already been declared and have been assigned values).
Computers and Technology
1 answer:
Assoli18 [71]3 years ago
4 0

Answer:

The following code as follows:

Code:

max=name1;   //define variable max that holds name1 variable value.

if (strcmp(name2, max)>0)  //if block.

{

   max=name2;  //assign value to max.

}

if (strcmp(name3,max)>0)   //if block.

{

  max=name3; //assign value to max.

}

Explanation:

In the above code, we define a variable that is max. The data type of max variable is the same as variables "name1, name2, and name3" that is "char". In the max variable, we assign the value of the name1 variable and use if block statement two times. In if block, we use strcmp() function that can be defined as:

  • In first if block we pass two variables in strcmp() function that is "name2 and max" that compare string value. If the name2 variable is greater then max variable value so, the max variable value is change by name2 variable that is "max=name2".
  • In second if block we pass two variables in strcmp() function that is "name3 and max" that compare string value. If the name3 variable is greater then max variable value so, the max variable value is change by name3 variable that is "max=name3".

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Lady_Fox [76]

Cybersecurity breaches in the workplace generally happen because:

  • People deliberately try to hack into the network people.
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<h3>What are the three main causes of security breaches?</h3>

The major reasons for data breaches are:

  • Old, Unpatched Security Vulnerabilities.
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  • Malware, etc.

Therefore, Cybersecurity breaches in the workplace generally happen because:

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5 0
2 years ago
Select the correct answer from each drop-down menu.
xz_007 [3.2K]

Answer:

Maths operators

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5 0
3 years ago
A computer program is tested by 5 independent tests. If there is an error, these tests will discover it with probabilities 0.1,
Svetllana [295]

Answer:

0.8488

Explanation:

Let E =error found by test 1

Let F=error found by test 2

Let G=error found by test 3

Let H=error found by test 4

Let I= error found by test 5

Given P(E)=0.1, P(F)=0.2, P(G)=0.3, P (H)= 0.4, P (I)=0.5

therefore P(notE)=0.9, P(notF)=0.8, P(notG)=0.7, P(not H)=0.6, P (notI)=0.5

Tests are independent P(not E & not F &not G & not H & not I=P(notE)*P(notF)*P(notG)*P (notH)*P (not I) =0.9*0.8*0.7*0.6*0.5 =0.1512

P(found by at least one test)= 1- P(not found by any test)=1-P(not E& not F & not G & not H & not I ) = 1-0.1512 = 0.8488

5 0
3 years ago
Match the spacing options to their meanings.
Maslowich

Before text = indents paragraph to the right  

First line = indents the start of a paragraph

Register-true = formats page styles  

Line spacing = manages space between two lines  

The first line always gets indent to specify that it is a start of the paragraph

Line spacing always focus on the number of spaces between lines. There are various values available to give spacing according to the need. Register- true is used to format all the page styles and do other related configurations.

3 0
3 years ago
Read 2 more answers
The Sieve of Eratosthenes is an elegant algorithm for finding all the prime numbers up to some limit n. The basic idea is to fir
IRISSAK [1]

Answer:

Check the explanation

Explanation:

#!usr/bin/python

#FileName: sieve_once_again.py

#Python Version: 2.6.2

#Author: Rahul Raj

#Sat May 15 11:41:21 2010 IST

 

fi=0 #flag index for scaling with big numbers..

n=input('Prime Number(>2) Upto:')

s=range(3,n,2)

def next_non_zero():

"To find the first non zero element of the list s"

global fi,s

while True:

if s[fi]:return s[fi]

fi+=1

def sieve():

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limit=(s[-1]-3)/2

largest=s[-1]

while True:

m=next_non_zero()

fi=s.index(m)

if m**2>largest:

primelist+=[prime for prime in s if prime] #appending rest of the non zero numbers

break

ind=(m*(m-1)/2)+s.index(m)

primelist.append(m)

while ind<=limit:

s[ind]=0

ind+=m

s[s.index(m)]=0

#print primelist

print 'Number of Primes upto %d: %d'%(n,len(primelist))

if __name__=='__main__':

sieve()

4 0
3 years ago
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