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o-na [289]
3 years ago
13

In the Cash Now lottery game there are 8 finalists who submitted entry tickets on time. From these 8 tickets, three grand prize

winners will be drawn. The first prize is one million dollars, the second prize is one hundred thousand dollars, and the third prize is ten thousand dollars. Determine the total number of different ways in which the winners can be drawn. (Assume that the tickets are not replaced after they are drawn.)
Mathematics
1 answer:
alexgriva [62]3 years ago
3 0

Answer:

The number of ways is  \left n} \atop {}} \right. P_r  =  336

Step-by-step explanation:

From the question we are told that

   The number of tickets are   n = 8

    The number of finalist are r   =3

Generally the number of way by which this winners can be drawn and arrange in the order of   1^{st} , \  2nd ,  \  3rd    is mathematically represented as

             \left n} \atop {}} \right. P_r  =  \frac{n\ !}{(n-r) !}

substituting values

             \left n} \atop {}} \right. P_r  =  \frac{ 8!}{(8-3) !}

           \left n} \atop {}} \right. P_r  =  \frac{ 8* 7*6*5*4*3*2*1}{ 5*4*3*2*1}

           \left n} \atop {}} \right. P_r  =  336

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The sum of six times a number and thirteen is five less than the product of three and the number
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Answer:

1 and 1/3

Step-by-step explanation:

I got this because you can first take 13-5 which is 8 then you can divide 8 by 6 to get your final answer.

Hope this helps.

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grin007 [14]
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Step-by-step explanation: diameter=10 in

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3 0
3 years ago
Can Anybody Help me?
Leviafan [203]

Answer:

x=8, y=-1

Step-by-step explanation:

The figure is said to be a rectangle, which means opposite sides have to be equal in length. From this, we can write a system of equations:

5x-2y=42

2x+3y=13

There are a number of ways to solve this but I'll go with elimination--that means you need to try to remove one variable first by manipulating the equations and solve for the other variable. Then you use the solution to solve for the variable you initially removed. That sounds confusing, but let me show you how to do it.

If you multiply the first equation by 3 and the second equation by 2, you'll have have:

15x-6y=126

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Now, we can add these two equations. The y will cancel out, so we can easily solve for x.

19x=152

x=8

Use this value of x to substitute back into either of the original equations to find y.

5(8)-2y=42

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