3x + 15 - 9 = 2(x +2)
3x + 6 = 2(x +2)
3x + 6 = 2x + 4
3x + 6 - 2x = 2x - 2x + 4
x + 6 = 4
x + 6 -6 = 4 - 6
x = -2
Option C:
x = 6 units
Solution:
QR = 7 units, RS = 5 units, UT = 4 units and ST = x
<em>If two secants intersect outside a circle, the product of the secant segment and its external segment s equal to the product of the other secant segment and its external segment.</em>
⇒ SR × SQ = ST × SU
⇒ 5 × (5 + 7) = x × (x + 4)
⇒ 5 × 12 = x² + 4x
⇒ 60 = x² + 4x
Subtract 60 from both sides.
⇒ 0 = x² + 4x - 60
Switch the sides.
⇒ x² + 4x - 60 = 0
Factor this expression, we get
(x - 6)(x + 10) = 0
x - 6 = 0, x + 10 = 0
x = 6, x = -10
Length cannot be in negative measures.
x = 6 units
Option C is the correct answer.
Answer:
Yes.
Step-by-step explanation:
It is a fraction.
Well if 5+5=10 adding 1 would give you 11. Or you could do 6+6=12 and then subtract 1. Both 5+5 and 6+6 are doubles facts.
Formula and set up:
A = P(1 + r/n)^(nt)
You want A.
A = 1200(1 + (0.06)/2)^(0.06)(2)
Plug right side into calculator to find A.