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vesna_86 [32]
3 years ago
9

Is 1/19 a rational number?

Mathematics
2 answers:
ch4aika [34]3 years ago
8 0

Answer:

Yes.

Step-by-step explanation:

It is a fraction.

m_a_m_a [10]3 years ago
4 0
It is a rational number
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What is the solution of this equqtion? 4+ 1/4 w=6​
ale4655 [162]

Answer:

w = 8

Step-by-step explanation:

4+ 1/4 w=6​

Subtract 4 from each side

4-4+ 1/4 w=6​-4

1/4w = 2

Multiply each side by 4

4* 1/4 w=2*4

w = 8

4 0
3 years ago
How many 3/4s are in 1​
kirza4 [7]

Answer and Step-by-step explanation:

There is 1\frac{1}{3} \frac{3}{4} in the number 1.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

5 0
3 years ago
Simplify 5t+ (-3) - ((7t + 5) -( 8-39).<br><br>A -4 <br>B 4<br>C -10t<br>D 10t​
brilliants [131]

I guess it's A -4 sorry if it's wrong answer

3 0
3 years ago
The width of a golden rectangle is 15 feet. Find the perimeter of the rectangle to the nearest foot.
topjm [15]

Answer:

79 ft

Step-by-step explanation:

Golden rectangle side ratios   1 : (1+sqrt5 )/2

      (approx  1: 1.618)

15 + 15   +  2*15*1.618 = <u>~79 ft </u>

BUT perhaps the 15 is the 1.618 side

15/1.618 + 15/1.618   + 15 + 15   ~ 49 feet

3 0
2 years ago
Solve square root of x + square root of x+2 = 2
andrew-mc [135]

The value of x is \frac{1}{4}

Step-by-step explanation:

Given:

\sqrt{x} +  \sqrt{x + 2} = 2

Rearranging the radical on left side,

\sqrt{x + 2} = 2 - \sqrt{x}

Power on both sides,

(\sqrt{x + 2})^{2}  = (2 - \sqrt{x})^{2}

Simplifying the left,

x + 2 = (2 - \sqrt{x} )^{2}

For the RHS equation, use the property of (a-b)² = (a²-2ab+b²),

=  > x + 2 =  {2}^{2} - (2 \times 2 \sqrt{x}) + ( \sqrt{x})^{2}

Now calculating its powers,

=  > x + 2 = 4 - 4\sqrt{x} + x

Now sending -4√x to the LHS (left side), its sign becomes plus (+),

=  > 4 \sqrt{x} = 4 + x - x - 2

Now the +x and -x will be cancelled,

=  > 4 \sqrt{x} = 4 - 2

=  > 4 \sqrt{x} = 2

Bringing 4 to the right side, it becomes the denominator,

=  >  \sqrt{x} =  \frac{2}{4}

=  >  \sqrt{x} =  \frac{1}{4}

Now powering both sides,

=  > ( \sqrt{x})^{2} = ( \frac{1}{2})^{2}

=  > x =  \frac{1}{4}

4 0
2 years ago
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