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valentina_108 [34]
3 years ago
10

Tickets to the school musical are $5.00 for adults and $2.50 for students. If the total value of the tickets sold was $687.50 an

d 50 more students
bought tickets than adults, how many adults and students bought tickets?
Mathematics
1 answer:
Masja [62]3 years ago
4 0

Answer:

Your answers should be a = 135 adult tickets and s = 186 student tickets.

Step-by-step explanation:

1. Solving for variable s by manipulating variable a:

a + s = 321

a = 321 - s (subtract s to the other side to get a by itself)

$3.50(321-s) + $2.50s = $937.50 (substitution from step 2)

$1123.50 - $3.50s + $2.50s = $937.50 (distributive property)

$1123.50 - $1.50s = $937.50 (combine like terms)

-$1.00s = -$186 (subtraction property of equality)

s = 186 student tickets.

2. Solving for variable a by manipulating variable s:

a + s = 321

s = 321 - a

$3.50a + $2.50(321-a) = $937.50

$3.50a + $802.50 - $2.50 a = $937.50

$1.00a = $135

a = 135 adult tickets.

If you plug both numbers into the original equations, they should come out to be true equations. 135 + 186 = 321 and $472.5 + $465 = $937.5, so these two numbers are your answers for a and s accordingly.

Using the elimination method, we need to eliminate one of the variables by a process of subtraction or addition depending on the case. We can use multiplication or division before eliminating in order to eliminate.

a + s = 321

3.50a + 3.50s = 1123.50 (multiply entire equation by 3.50 in order to eliminate variable a by subtraction)

Now, we can use elimination:

3.50a + 3.50s = 1123.50

3.50a + 2.50s = 937.50

0a + 1s = 186, or s = 186 student tickets.

The same process can be used to solve for variable a. Your answers should be a = 135 adult tickets and s = 186 student tickets.

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