BC = a
AC = b
ACB = C
To find the area of such triangle we are going to use the formula;
1/2 * a * b * sine C
Substitute values.
1/2 * 4 * 4 * sine 45
= 5.65^2
Therefore the area of the triangle is 5.65^2
First count the fully shaded boxes than count each half knowing two halfs equal one
1)32
2)22
3)22
4)12
Well one is def 10 but im not sure what the other one is
