All categories

4 years ago

Write a equation in slope intercept form of a line parallel to y=6x-3

Mathematics

2 answers:

eduard4 years ago

8 0

Answer:

y= 6x+3

Step-by-step explanation:

So whenever we use parallel lines trying to change them into slope intercept what you have to do is remember that parallel lines have to have the same slope.

GenaCL600 [577]4 years ago

7 0

Answer:

y=6x+3

Step-by-step explanation:

A line that is parallel to another line, has the opposite slope of the first line.

You might be interested in

A biker rides for h hours at a speed of s miles per hour and travels d miles. Which equation models the relationship?

Luda [366]

I believe it’s B good luck!!

7 0

3 years ago

Read 2 more answers

Which of the following sets of ordered pairs represents a function?

Zinaida [17]

Shouldn't the answer be: (-1,4),(1,4),(2,4),(-2,4)

8 0

3 years ago

Read 2 more answers

Triangles and algebra

Elanso [62]

Hello from MrBillDoesMath!

Answer:

x = 10

Discussion:

A plane triangle contains 180 degrees. Adding the angles in the triangle shown in #8 gives

(4x + 7) + (3x + 13) + 90 = 180

Note the "right angle" shown in the triangle has been replaced by its 90 degree equivalent in the above equation.

Combining like terms gives

( 4x + 3x) + (7 + 13) + 90 = 180

7x + 20 + 90 = 180 => (subtract 90 from each side)

7x + 20 + 90 - 90 = 180 - 90 = 90 =>

7x +20 = 90 => (subtract 20 from each side)

7x + 20 -20 = 90 -20 =>

7x = 70 =>

x 70/7 =10.

Thank you,

MrB

3 0

4 years ago

so billy has 10 apples if he subtracts it by 6 then times it by 3 then divides it by 2 what does he get?

geniusboy [140]

Answer:

Step-by-step explanation:

3 × (10 - 6) ÷ 2 =?

The strategy that we are using here is PEMDAS:

First, you subtract 6 from 10 which is 4. 10 - 6 =4

Next, you multiply 4 by 3. 4 × 3 = 12

Then, you divide 12 by 2. 12 ÷ 2 = 6

Your answer is 6.

Your welcome. Showed my work below.

5 0

3 years ago

(√x+1/√x)^2find dy/ dx and substitute 2 in dy/ dx

lions [1.4K]

Hello,
That's better.

I suppose $y=( \sqrt{x} + \dfrac{1}{ \sqrt{x} } )^2 \\

y'=2*( \sqrt{x} + \dfrac{1}{ \sqrt{x} } )*( \dfrac{1}{2 \sqrt{x} } - \dfrac{3}{2x \sqrt{x} } )$

If x=2 then
$y'=2*( \sqrt{2} + \dfrac{1}{ \sqrt{2} } )*( \dfrac{1}{2 \sqrt{2} } - \dfrac{3}{2*2* \sqrt{2} } )\\
=2* \dfrac{2+ \sqrt{2} }{ \sqrt{2} } * \dfrac{1}{4*\sqrt{2} } *(-1)\\
=- \dfrac{2+ \sqrt{2} }{4}$

3 0

3 years ago